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Oksi-84 [34.3K]
3 years ago
15

IQ test if a+b=76 a-b=38 a divided by b

Mathematics
1 answer:
ankoles [38]3 years ago
6 0
The answer all together that i got was 42 i dont know for fact if that is the correct answer but its woth a shot
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What is the mode of the data set? 1, 1, 2, 1, 3, 2, 2, and 3
slavikrds [6]

maybe: Mean

=

2.22

Median =

2

Mode =

1

and

3

Explanation:

Mean:

¯

x

=

1

+

2

+

1

+

2

+

1

+

3

+

3

+

4

+

3

9

=

20

9

=

2.22

Median: First we put the numbers in order from lowest to highest:

1

,

1

,

1

,

2

,

2

,

3

,

3

,

3

,

4

The median is the number that has the central position.

Median

=

2

Mode: it is the number that appears the most times. In this case, both

1

and

3

appear the same number of times, so they are both modes.

hope this helps!

8 0
3 years ago
Read 2 more answers
One cell phone plan costs $29.94 per month plus $.10 for MB of data. Another plan costs $32.99 per month
liubo4ka [24]
Plan 1 = 29.94 + 0.10x
Plan 2 = 32.99 + 0.05x

Plan 1 = Plan 2
29.94 + 0.10x = 32.99 + 0.05x
0.10x - 0.05x = 32.99 - 29.94
0.05x = 3.05
0.05x/0.05 = 3.05/0.05
x = 61

61 MB of data is needed to make both plan equal.

to check: x = 61

29.94 + 0.10(61) = 32.99 + 0.05(61)
29.94 + 6.10 = 32.99 + 3.05
36.04 = 36.04

5 0
4 years ago
Create an algebraic expression to solve the following problems.
daser333 [38]

Answer:

Step-by-step explanation:

x is the number of GB

f(x) is the cost in dollars

f(x) = 10x

Bill for 6 GB = f(6) = 60

:::::

f(x) = 8x+15

Bill for 8 GB = f(10) = 95

:::::

f(x) = 5x+30

Bill for 2 GB = f(2) = 40

7 0
3 years ago
A factory produces some batteries daily. 7/8 of the batteries are packaged immediately. 2/3 of the
frozen [14]

Answer:

\[\frac{1}{24}\]

Step-by-step explanation:

Let the total number of batteries produced daily be represented by x.

7/8 of the batteries are packaged immediately.

So the total number of packaged batteries = \[\frac{7x}{8}\]

Remaining batteries = \[x-\frac{7x}{8}\]

= \[\frac{x}{8}\]

Two third of the remaining batteries are sent to charity.

So the total number of batteries sent to charity= \[\frac{2}{3} * \frac{x}{8}\]

= \[\frac{x}{12}\]

Remaining batteries are faulty.

So the total number of faulty batteries = \[\frac{x}{8} - \frac{x}{12}\]

= \[\frac{3x - 2x}{24}\]

= \[\frac{x}{24}\]

So the faction of batteries which are faulty =

= \[\frac{x}{24} \div x\]

= \[\frac{1}{24}\]

3 0
3 years ago
Any girls wana hand out their snaps
Nadya [2.5K]

Answer:

nah I'll pass, I just need the points :)

7 0
3 years ago
Read 2 more answers
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