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sergiy2304 [10]
3 years ago
13

What is 21/56 and 63/81 in simplest form

Mathematics
1 answer:
Arisa [49]3 years ago
7 0
21/56=0.375
63/81=0.777777 #This is a repeating decimal.
~JZ
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konstantin123 [22]

Answer: A

Step-by-step explanation:

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3 years ago
-x -7y = 14<br> -4x -14y =28
koban [17]

Given:

\to \bold{-x -7y = 14}\\\\\to \bold{-4x -14y =28}\\\\

To find:

\bold{x \ and \ y}=?

Solution:

\to \bold{-x -7y = 14}..................... (i) \\\\\to \bold{-4x -14y =28} .................(ii)\\\\

Solving the equation (i):

\to \bold{-x -7y = 14} \\\\  \to \bold{-x=  14+7y} \\\\    \to \bold{x= - (14+7y)} \\\\

Putting the value of x into the equation (ii):

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Putting the value of y into the equation (i):

\to \bold{-x -7(-2) = 14}\\\\\to \bold{-x +14 = 14}\\\\\to \bold{-x  = 14-14}\\\\\to \bold{x  = 0}\\\\

So, the value of \bold{x=0 \ and\  y= -2}\\\\

Learn more:

brainly.com/question/10151402

7 0
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 A barber has already cut for peoples hair today. Every 10 minutes another person comes to the Barber to get a haircut. Write
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Answer:

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3 years ago
State University uses thousands of fluorescent light bulbs each year. The brand of bulb it currently uses has a mean life of 600
Ipatiy [6.2K]

Answer:

The test statistic is t = 2.5.

The p-value of the test is of 0.007 < 0.05, which means that the evidence supports the manufacturer's claim at the .05 significance level.

Step-by-step explanation:

Mean life of 600 hours. Test if it is more.

At the null hypothesis, we test if the mean is of 600 hours, that is:

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At the alternative hypothesis, we test if the mean is of more than 600 hours, that is:

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The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

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This means that \mu = 600

Suppose 100 bulbs were tested and found to have a mean of 625 hours with a standard deviation of 100.

This means that n = 100, X = 625, s = 100.

Value of the test-statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{625 - 600}{\frac{100}{\sqrt{100}}}

t = 2.5

The test statistic is t = 2.5.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 625 hours, which is a right-tailed test, with t = 2.5 and 100 - 1 = 99 degrees of freedom.

Using a t-distribution calculator, this p-value is of 0.007.

The p-value of the test is of 0.007 < 0.05, which means that the evidence supports the manufacturer's claim at the .05 significance level.

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I m s o d u m b t h a t i c a n t e v e n d o 1 + 1 s o i n e e d h e l p
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Answer:

1 + 1 = 2

Step-by-step explanation:

:)

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Read 2 more answers
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