Slope formula : (y2 - y1) / (x2 - x1)
(2,-2)....x1 = 2 and y1 = -2
(4,1)...x2 = 4 and y2 = 1
now we sub into the slope formula and solve for the slope
slope = (1 - (-2) / (4 - 2) = (1 + 2) / 2 = 3/2
now we use y = mx + b
slope(m) = 3/2
use either of ur points....(4,1)...x = 4 and y = 1
now sub into y = mx + b formula and find b, the y int
1 = 3/2(4) + b
1 = 6 + b
1 - 6 = b
-5 = b
so ur equation is : y = 3/2x - 5 <==
Answer:
CEFA
Step-by-step explanation:
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Hope this helps
To look for the area of a sector of a circle, the following formula is used:
Area = ( n / 360 ) * pi * r^2
Where: n = measure of arc in degrees
pi = 3.1416
r = radius
Since we are already given all of the needed parts of the formula, direct substitution is done, as shown below:
Area = ( n / 360 <span>) * pi * r^2
</span>Area = ( 45 / 360 ) *3.1416 * (8)^2
Area = 25.133 in^2
Therefore, the area of the sector of the circle is 25.133 sq. in.
Answer:
y=(-5/2) x -7
Step-by-step explanation:
y=mx+b
m=(-5/2)
To find b:
3=(-5/2)times"x" + b
3=(-5/2)times(-4) + b
3= 10 +b; b=-7
y=(-5/2) x -7
4.4a-2.9a= 1.5a
6.8-7.3=(-0.5)
Ans: 1.5a+(-0.5) OR 1.5a-0.5
