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Gwar [14]
3 years ago
14

wo companies offer different charges for text messaging. Company 1 charges $0.04 per text message, while Company 2 charges rates

according to the table. Which company offers the cheapest plan for up to 500 text messages?
Mathematics
2 answers:
ira [324]3 years ago
8 0
Tell me how much company 2 charges per rate and I can help you. There was no table attached to see.
Greeley [361]3 years ago
8 0

Answer:Company one cause the equation for it is y=0.04x. If you do y=0.04(500) u get 20$ as the total.

Step-by-step explanation:

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Elena L [17]

Answer:

9:13

Step-by-step explanation:

36:52

divide both by two

18:26

divide both by 2

9:13

6 0
3 years ago
I DONT UNDERSTAND HELP
Taya2010 [7]

Step-by-step explanation:

By Geometric mean property:

{16}^{2}  = x \times 3x \\  \\  \therefore \: 3 {x}^{2}  =  {16}^{2}  \\  \\ \therefore \:  {x}^{2}  =   \frac{{16}^{2} }{3} \\  \\ \therefore \:  {x}  =   \sqrt{ \frac{{16}^{2} }{3} }  \\  \\ \therefore \:  {x}  =   {  \frac{16}{ \sqrt{3} } } \\  \\ \therefore \:  {x}  =   {  \frac{16 \sqrt{3} }{ 3} } \\  \\ \therefore \:  {x}  =   {  \frac{16  \times 1.732}{ 3} } \\  \\ \therefore \:  {x}  =   {  \frac{27.712}{ 3} }\\  \\ \therefore \:  {x}  =   9.23733333 \\  \\  \huge \red{ \boxed{ \bold{\therefore \:  {x}  =   9.24}}}

8 0
4 years ago
A set average city temperatures in August are normally distributed with a mean of 21.25 degrees Celsius and a standard deviation
Ainat [17]

Answer:

The proportion of temperatures that lie within the given limits are 10.24%

Step-by-step explanation:

Solution:-

- Let X be a random variable that denotes the average city temperatures in the month of August.

- The random variable X is normally distributed with parameters:

                           mean ( u ) = 21.25

                           standard deviation ( σ ) = 2

- Express the distribution of X:

                           X ~ Norm ( u , σ^2 )

                           X ~ Norm ( 21.25 , 2^2 )

- We are to evaluate the proportion of set of temperatures in the month of august that lies between 23.71 degrees Celsius and 26.17 degrees Celsius :

                           P ( 23.71 < X < 26.17 )

- We will standardize our limits i.e compute the Z-score values:

                          P (  (x1 - u) / σ < Z < (x2 - u) / σ )

                          P (  (23.71 - 21.25) / 2 < Z < (26.17 - 21.25) / 2  )

                          P ( 1.23 < Z < 2.46 ).

- Now use the standard normal distribution tables:

                          P ( 1.23 < Z < 2.46 ) = 0.1024

- The proportion of temperatures that lie within the given limits are 10.24%

4 0
3 years ago
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lesya [120]
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3 0
4 years ago
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elena-s [515]

Answer:

x = 35

Step-by-step explanation:

The sum of the exterior angles of a polygon = 360°

Then

1 exterior angle = 360° ÷ 8 = 45° , so

x + 10 = 45 ( subtract 10 from both sides )

x = 35

3 0
3 years ago
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