MN = √2
it comes from √(1^2 + 1^2) = √2 (use phytagoras)
LK = 2 x MN = 2 √2
NK = √(2^2 + 1^2) = √5
ML = NK = √5
so the perimeter
√2 + 2 √2 + √5 + √5
3 √2 + 2 √5
Answer:
.
Step-by-step explanation:
Answer:
The bird has to fly 7.5 m
Step-by-step explanation:
Please see diagram in attached image.
Notice that there is a right angle triangle that defines the situation, and you know two elements of such triangle;
1) one acute angle (
), and
2) the side opposite to that angle.
What you need to find is the side adjacent to the angle, which is what the bird needs to fly horizontally to be above the fish. We named that "x".
The trig function that relates such triangle elements is the tangent:
which rounded to the nearest tenth is: 7.5 m
9514 1404 393
Answer:
a) x = -1, x = 4
b) y = x^2 -3x -4
Step-by-step explanation:
a) We observe the x-intercepts are x = -1 and x = 4. These are the solutions to y = 0, which is usually what we want in cases like this.
The solutions are x=-1 and x=4.
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b) We know two of the factors are (x +1) and (x -4). There may be an additional constant factor for vertical scaling. One point we can check is the y-intercept.
y = a(x +1)(x -4)
For x=0, this is ...
y = a(1)(-4) = -4a
The y-intercept is y = -4, so we have a=1.
The factored equation is ...
y = (x +1)(x -4)
Multiplying this out gives the equation in standard form:
y = x^2 -3x -4
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<em>Additional comment</em>
Your teacher may want the standard form equation to be ...
x^2 -3x -4 = 0
This is the equation of two specific points: x=-1 and x=4. It is not the equation of the graph.
