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vagabundo [1.1K]
3 years ago
9

Help please! 1/2x + 3 < 4x - 7 ANSWERS ARE BELOW

Mathematics
1 answer:
nexus9112 [7]3 years ago
4 0
This one is harder than wby other
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What are the roots of x in -10x^2+12x-9=0
dezoksy [38]
They do not exist.  The parabola never crosses the x-axis (which is the same thing as the roots).
6 0
4 years ago
There were 135 cars in a rally each driver paid a $25 fee to participate in the rally how much money did the drivers play in all
charle [14.2K]

Total numbers of cars present in the rally is  135

Amount paid by a single driver to participate in the rally = $25

Total amount generated by the participation fee from each driver is equal to the sum of amount paid by all the 135 cars.

Since we cannot add $25 for 135 times, we use multiplication operation.

Total amount = amount paid by one single driver multiplied by the total number of cars.

Total amount = 135 * 25 = 3375 $ .... Answer


7 0
3 years ago
In the expression 5n- 2m/7 + 3/4, what is the constant?<br> A. -2/7<br> B. 3/4<br> C. 5<br> D. 21
gavmur [86]

Answer:

Step-by-step explanation:

For this case we have the following expression:

 5n-2m / 7 + 3/4

 We have the following variables:

 variable 1: n

 variable 2: m

 The terms that accompany the variables are coefficients

 Therefore, the term that does not accompany the variables is the constant of the expression.

 The constant is: 3/4

 Answer:

 the constant is 3/4

6 0
4 years ago
The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the
Mumz [18]
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well   \bf v=rw\qquad &#10;\begin{cases}&#10;v=\textit{linear velocity}\\&#10;r=radius\\&#10;w=\textit{angular velocity}\\&#10;----------\\&#10;r=18in\\&#10;w=1302\frac{\pi }{min}&#10;\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}&#10;\\\\\\&#10;v=\cfrac{23436\pi\ in}{min}

now, how much is that in miles/hrs?  well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus   \bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}

notice, after all the units cancellations, you're only left with mi/hrs
4 0
3 years ago
Based on the graph, what are the approximate solutions to the equation -3+8=(0.25)x?
ivanzaharov [21]
We know that
the solution of the equations system is the intersection both graphs 

first point of intersection is in the interval [-2,-1]
second point of intersection is in the interval [2,3]

<span>the only option that meets these two conditions is the option D
</span>-1.9 and 2.6
8 0
3 years ago
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