Answer:
the new perimeter will be 1/3 time the perimeter of the original rectangle
Step-by-step explanation:
Answer:
-63
Step-by-step explanation:
First, it depends how you want to solve the system. The easiest way is to solve by elimination. Eliminate the 2 s. Therefore, 4x = 8. Divide by 4 to find x. After dividing by 4, x=2. To find the y plug in 2 for x in the original equation. Try for the first one. 2 +2y =3. Subtract 2 from both sides of the equation. Then you get 2y =1. Divide by 2 in both sides and you get y = 1/2.
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.
Because we know 3 and -1 (multiplicity 2) are both roots, the last root 
is such that we can write
There are a few ways we can go about finding , but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be 
.
Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have
so the missing root is 3.
Other things we could have tried that spring to mind:
- three rounds of division, dividing the quartic polynomial by 
, then by 
twice, and noting that the remainder upon each division should be 0
- rational root theorem
