Sometimes
1. The radical expression
![\sqrt[n]{}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B%7D%20)
with even n requires <span>a variable with positive quantity. For example, if you have
![\sqrt[4]{x^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20)
, then always
.
</span>
2. If you have radical expression
with odd n, ia variable may be arbitrary. For example, for
![\sqrt[7]{x}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7Bx%7D%20)
you can consider all real x.
Isosceles triangle
y = 72 yd
x^2 = 72^2 + 72^2
x^2 = 2(72^2)
x = 72√2 yd
Answer:
-1 and -2
Step-by-step explanation:
cuz smarts
Answer:
C. 3x^2 -13x + 7
Step-by-step explanation:
Lets start in the ones place:
+3
- (-4)
_______
+7
Now go to the tens place:
-5x
-(8x)
________
-13x
Lastly, go to the hundreds place:
6x^2
-(3x^2)
_________
3x^2
So, the correct answer is "3x^2 -13x + 7", which is C.
I hope this helps! :)
Answer:
the error is in step 2.
0.25x was added to -0.75x with an incorrect result of +0.50x.
Step-by-step explanation:
The incorrect step is ...
Step 2: negative 1.50 = 0.50 x
This is the result of an attempt to add 0.25x to both sides of the equation. The correct step would be ...
-1.50 -0.25x = -0.75x . . . . . . . result from Step 1
-1.50 -0.25x +0.25x = -0.75x +0.25x . . . . . add 0.25x to both sides
-1.50 = -0.50x . . . . . . . . . . . . . the correct result from the addition (Step 2)
__
The correct result is ...
x = -1.50/-0.50 = 3 . . . . . Step 3
