First you do absolute valve which will make it x+1+5=8 then you move x to one side so -x on both sides and -8 on both sides -8+1+5=-x
Then it would be -2=-x and sense you can’t have -x you would have to divide both sides by -1 your answer would be 2=x
The most likely number of times that 3 was spun would be 2538
Answer:
x = theta = 0°
Step-by-step explanation:
Given the trigonometry function
Tan²x/2-2 cos x = 1
Tan²x-4cosx = 2 ... 1
From trigonometry identity
Sec²x = tan²x+1
tan²x = sec²x-1 ... 2
Substituting 2 into 1, we have:
sec²x-1 -4cosx = 2
Note that secx = 1/cosx
1/cos²x - 1 - 4cosx = 2
Let cosx. = P
1/P² - 1 - 4P = 2
1-P²-4P³ = 2P²
4P³+2P²+P²-1 = 0
4P³+3P² = 1
P²(4P+3) = 1
P² = 1 and 4P+3 = 1
P = ±1 and P = -3/4
Since cosx = P
If P = 1
Cosx = 1
x = arccos1
x = 0°
If x = -1
cosx = -1
x = arccos(-1)
x = 180°
Since our angle must be between 0 and 1 therefore x = 0°
So the first three possible values of g^2 + 3 are:
3, 4, 7
The first option is the correct one.
<h3>
Which ones are the first three possible values?</h3>
The set of the whole numbers is {0, 1, 2, 3...}
Then the first possible value is when g = 0.
0^2 + 3 = 3
The second possible value is when g = 1
1^2 + 3 = 4
The third possible value is when g = 2.
2^2 + 3 = 7
So the first three possible values of g^2 + 3 are:
3, 4, 7
The first option is the correct one.
If you want to learn more about whole numbers:
brainly.com/question/5243429
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