Answer:
Step-by-step explanation:
Hello!
The objective is to estimate the average time a student studies per week.
A sample of 8 students was taken and the time they spent studying in one week was recorded.
4.4, 5.2, 6.4, 6.8, 7.1, 7.3, 8.3, 8.4
n= 8
X[bar]= ∑X/n= 53.9/8= 6.7375 ≅ 6.74
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[376.75-(53.9²)/8]= 1.94
S= 1.39
Assuming that the variable "weekly time a student spends studying" has a normal distribution, since the sample is small, the statistic to use to perform the estimation is the student's t, the formula for the interval is:
X[bar] ± * (S/√n)
6.74 ± 2.365 * (1.36/√8)
[5.6;7.88]
Using a confidence level of 95% you'd expect that the average time a student spends studying per week is contained by the interval [5.6;7.88]
I hope this helps!
so, as you can see, the common difference is then -2, and the first term is clearly 8, thus
Answer: No
Step-by-step explanation: If you plug in 10 for y and 2 for x, the equation becomes 10=9(2), which is 10=18.
9.
V=s^3
V= 8^3
V=512
______________
8. V=2l+2w+2h
Substitute the numbers
2(8)+2 (7)+2 (6)
V= 42
______________________
7.
V=2/3 (pi)r
V= 2/3 (pi)(5)
V= 10.47
If it help you please pick as best Thank
Answer: 450
Step-by-step explanation:
You will do 50 times 9, and then you will get 450. You get this answer because you get 50 each day so you will need to multiply 50 times 9 to figure out how much she earns on the ninth day.