How do you multiply a whole number with a mixed number

1 answer:

6 0

You would change the whole number to a fraction by putting it over 1 and make the mixed number an improper fraction by multiplying the whole number part of the mixed number by the denominator and then and the numerator

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Which graph represents y = StartRoot x minus 4 EndRoot?

ozzi

The answer is for a fact c

3 0

1 year ago

C What is the missing hypotenuse length? * х 6 8

4vir4ik [10]

Step-by-step explanation:

By Pythagoras' Theorem, 6^2 + 8^2 = x^2.

x^2 = 36 + 64 = 100, x = 10.

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2 years ago

For what value of c does x^2−2x−c=4 have exactly one real solution? PLEASE HELP!!!!!!!

Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

$x^2-2x-(c+4)=0$ .

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic $ax^2+bx+d$ , the discriminant is $\sqrt{b^2-4ad}$ .

(The discriminant is more commonly known as $\sqrt{b^2-4ac}$ , but I changed the variable since we already have a $c$ in the quadratic given.)

In the quadratic above, we have $a=1$ , $b=-2$ , and $d=-(c+4)$ . Plugging this into the formula for the discriminant, we have

$\sqrt{(-2)^2-4(1)(-(c+4))$ .

Using the distributive property to expand and simplifying, the expression becomes

$\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.$