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uranmaximum [27]
3 years ago
13

1. If 9 students sharpen 18 pencils in 2 minutes, how many students will it take to sharpen 18 pencils in 1 minute?

Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0
A) If 9 students sharpen 18 pencils in 2 minutes,Then if the time is halved, it will take twice as many men to sharpen 18 pencils.Hence it will take 18 students to sharpen 18 pencils in one minute B) y & 1/x. Then y = K/x where K is our constant of proportionality.Then K = yx. When x = -64 and y = -16 then K = -64 * -16 = 1024. Option DC) When x = 3 y = 8. So for an inverse variation K as calculated from B = 3 * 8 = 24.Then when K = 24 and y = 6; we have 24 = 6x. Hence x = 4. Option A
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2 Probability and Stats questions!!
mart [117]
 1) To find the confidence interval 
the sample mean x = 38     σ = 9; n = 85;
The confidence level is 95% (CL = 0.95) <span>CL = 0.95
so α = 1 – CL = 0.05   
</span><span>α/2 = 0.025   </span>Z(α/2) = z0.025  
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
<span>EBM = (1.645)*(9)/(85^0.5)=1.6058</span> x - EBM = 38 – 1.6058 = 36.3941 <span> x + EBM = 38 + 1.6058 = 39.6058
</span>The 95% confidence interval is (36.3941, 39.6058).
The answer is the letter D
<span>The value of 40.2 is <span>within the 95% confidence interval for the mean of the sample

</span></span>2) To find the confidence interval  <span>
<span>the sample mean x = </span>76     σ = 20; n = 102; </span><span>
The confidence level is 95% (CL = 0.95) CL = 0.95 
so α = 1 – CL = 0.05   
α/2 = 0.025   Z(α/2) = z0.025 
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975 
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
EBM = (1.645)*(20)/(102^0.5)=3.2575 x - EBM = 76 – 3.2575 = 72.7424 </span>  x + EBM = 76 + 3.2575 = 79.2575 <span> 
The 95% confidence interval is (</span>72.7424 ,79.2575).<span>
The answer is the letter </span>A and the letter D<span>
The value of 71.8 and 79.8 <span> are </span> outside<span> the 95% confidence interval for the mean of the sample</span></span>
5 0
3 years ago
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