Y = X - 9
so 3X +2Y = 2
will be 3X +2×(X-9) = 2
3X + 2X -18 = 2
5X = 2 + 18
5X = 20
X = 4
Y = X - 9
Y = 4-9
Y = -5
the answer will be A) (4,-5)
please mark me as brainlest

4 0

3 years ago

On December 1 at 10 P.M., the bright star Procyon will just be rising on the eastern horizon. At approximately what time would y

Citrus2011 [14]

Answer:

8 : 24 P.M

Step-by-step explanation:

Data provided in the question:

On December 1 bright star Procyon will just be rising on the eastern horizon at 10 P.M

Now,

we know that Stars rise 4 minutes earlier each night

Therefore,

24 days later i.e after 24 nights the total early time

= 24 days × 4 minutes per day

= 96 minutes

= 1 hour 36 minutes early

Hence,

on Christmas Day the star will rise at 1 hour 36 minutes early than 10 P.M

= 8 : 24 P.M

7 0

3 years ago

An English professor determined the mean of her final exam scores to be 78 with a standard deviation of 6.3. Find the minimum an

Morgarella [4.7K]

Solution: We are given:

$Mean =78, Standard-deviation =6.3$

We know that a usual values of the test scores falls within 2 standard deviation from the mean.

Therefore, the minimum usual test score is:

$Mean - 2 Standard-deviation$

$78-2 \times 6.3$

$78-12.6$

$65.4$

The maximum usual test score is:

$Mean + 2 Standard-deviation$

$78+2 \times 6.3$

$78+12.6$

$90.6$

Therefore, the minimum and maximum “usual” values of the test scores are:

65.4 and 90.6

5 0

3 years ago

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