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Andrej [43]
3 years ago
13

-2(x-3)=4 solving for x

Mathematics
1 answer:
Eva8 [605]3 years ago
3 0

Answer:

x = 1

Explanation:

−2(x − 3) = 4

[ \ Simplify \ both \ sides \ of \ the \ equation \ ]

−2(x − 3) = 4

(−2)(x) + (−2)(−3) = 4 [ \ Distribute \ ]

−2x + 6 = 4

[ \ Subtract \ 6 \ from \ both \ sides \ ]

−2x + 6 − 6 = 4 − 6

−2x = −2

[ \ Divide \ both \ sides \ by \ -2 \ ]

-2x / -2 = -2 / -2

x = 1

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Two cars start from the same point driving in opposite directions. Both cars drive 6miles. One car stops, the other car makes a
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Answer:

  • <u>14.4 mile</u>²

Explanation:

1. By driving 6 miles each, the cars will be 6 miles + 6 miles = 12 miles appart.

2. When one car stops and the other car makes a 90° left-hand turn and drive 8 miles, you can model the situation with a right triangle, where one leg is 12 miles, the other leg is 8 miles, and the hypotenuse is the distance that separates the cars.

Hence, you must use Pythagoras to find that distance.

3. Pythagoras

  • hypotenuse² = leg₁² + leg₂²

  • hypotenuse = (12 mile)² + (8 mile)² = 144 mile² + 64 mile² = 208 mile²

  • hypotenuse=\sqrt{208mile^2}=14.4mile^2, which is rounded to the neartest tenth of a mile.
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3 years ago
david is 8 years older than stephen and 2 years younger than Graham. if Neil is 7 years younger than Graham, how much older than
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Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,
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A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
d^2=3^2+2^2
d^2=9+4
d^2=13
d= \sqrt{13}
We can conclude that the distance between my house and the movie theater is \sqrt{13}

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
d^2=6^2+5^2
d^2=36+25
d^2=61
d= \sqrt{61}
We can conclude that the distance between the police station and the airport is \sqrt{61}

C. Distance form the park to the Fire Station:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance from the park to the Fire Station is \sqrt{10}

Distance from the stadium to the mall:
d^2=2^2+1^2
d^2=4+1
d^2=5
d= \sqrt{5}
We can conclude that the distance from the stadium to the mall is \sqrt{5}

D. What is the distance between your house and the mall?
Answer:
d^2=4^2+4^2
d^2=16+16
d^2=32
d= \sqrt{32}
d=4 \sqrt{2}
We can conclude that the distance between my house and the mall is 4 \sqrt{2}

What is the distance between the movie theater and the school?
answer:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance between the movie theater and the school is \sqrt{10}

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Using the table, we will see that the function is:

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Here we only have a table to work with, so we need to use that.

In the table, we can see the pairs:

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From that we can conclude that the function will be:

t(l) = 3*l

If you want to learn more about linear functions, you can read:

brainly.com/question/4025726

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