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Cloud [144]
3 years ago
8

Show me quadrilaterals shapes

Mathematics
2 answers:
Volgvan3 years ago
8 0
Anything with 4 sides is a quadrilateral like a rhombus square trapezoid and diamond
Aleksandr [31]3 years ago
7 0
Square
rombus
parallelogram
rectangle

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you are in charge of buying flowers for the flower beds around your school you cannot spend over $80 on flowers the flowers cost
Elena-2011 [213]
You can buy 7 flats of flowers. this is because 10.99 is close to 11.00, and 7 x 11 is 77. and you cant do 77 + 11 to get less then 80.

the answer: 7 flats of flowers

hope it helps :)
4 0
3 years ago
What are two numbers when multiplied get -40 and when added get 6
valentina_108 [34]
10 and -4. You multiply 10 times -4 to get -40 and you add 10 and -4 to get 6 
8 0
3 years ago
SDHGJSAFERTYUIKLJHGVFCDSWAERTUYIO
DedPeter [7]

Answer:

The answer is...

Step-by-step explanation:

rjbh4ewcnmdbscjewdishkfnciewjhdbfh

7 0
2 years ago
Read 2 more answers
Pls help me<br>I m giving brainliest <br>​
navik [9.2K]

Step-by-step explanation:

the general line equation format is

y = ax + b

a is the slope or gradient of the line. it is the ratio of "y coordinate change / x coordinate change".

b is the y-intercept, the y value when x = 0. we get this by putting one point into the equation and solve for b.

(i)

A (3, 5)

B (5, 9)

x changes by +2 (from 3 to 5).

y changes by +4 (from 5 to 9).

so, the slope (or gradient) is +4/+2 = 2

(ii)

the semi-finished equation is

y = 2x + b

let's use A to get b :

5 = 2×3 + b = 6 + b

b = -1

and the full equation is

y = 2x - 1

(iii)

for point (4, k) we get

k = 2×4 - 1 = 8 - 1 = 7

3 0
2 years ago
What is the constant term that completes the perfect square trinomial. y^2 + y
lara [203]
Y^2 + y

y^2 + y + 0.25 <=== the constant term is 0.25
(y + 0.5)(y + 0.5) =
(y + 0.5)^2

to find the constant, u take half of ur y coefficient (not the y^2 coefficient)....y^2 + 1y....ur y coefficient is 1......half of it is 0.5....u then square it....(0.5^2) = 0.25 ....this is ur constant
4 0
3 years ago
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