All categories

3 years ago

How can I solve this problem?

Mathematics

1 answer:

kap26 [50]3 years ago

8 0

a) 108°

Answer:

b) 54°

Step-by-step explanation:

a) By arc sum property of a circle.

$m\widehat {AEB} + m\widehat {AB} = 360°\\252° + m\widehat {AB} = 360°\\m\widehat {AB} = 360°- 252°\\\huge \red {\boxed {m\widehat {AB} = 108°}} \\$

b) In the given figure, DC is tangent to the circle with O at point A and AB is chord or secant. Therefore, by tangent secant theorem:

$m\angle BAC = \frac{1}{2} \times m\widehat {AB}\\\\\therefore m\angle BAC = \frac{1}{2} \times 108°\\\\\huge \purple {\boxed {m\angle BAC = 54°}}$

You might be interested in

Hey can you help me fast!!!

xenn [34]

Answer: 2 1/4 in.

Step-by-step explanation:

make the denominaters the same (4) and then subtract 20 3/4 - 18 2/4 which is 2 1/4.

hope this helps let me know if you need anything else! :')

5 0

3 years ago

Eileen and Tammy sell small and large boxes of apples for their school fundraiser. Eileen sells 2 small boxes of apples and 12 l

tester [92]

E=2x+12y
T=8x+8y I believe that’s how it should be if there are answer choices may I see?

6 0

3 years ago

A pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome). In the first sta

Akimi4 [234]

Answer:

95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

Step-by-step explanation:

We are given that a pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome).

In the first stages of a clinical trial, it was successful for 7 out of the 14 women.

Firstly, the pivotal quantity for 95% confidence interval for the true proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of women who find success with this new treatment = $\frac{7}{14}$ = 0.50

n = sample of women = 14

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the true proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.50-1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } }$ , $0.50+1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } }$ ]

= [0.238 , 0.762]

Therefore, 95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

4 0

4 years ago

Ayuda porfavor es urgente

san4es73 [151]

B for one and D for 2
Uno - B Dos - D

5 0

3 years ago

8 +7m = m +5m 5 +2n = -1 +4n

Dmitry_Shevchenko [17]

8 +7m=6m (combine like terms)
8=-m ( subtract 7m on both sides)
m=8 (divide by -1)

5=-1+2n ( subtract 2n on both sides)
6=2n (add 1 on both sides)
3=n (divide by 2 on both sides)

4 0

3 years ago