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IgorLugansk [536]
3 years ago
11

The number 2601 unsquared

Mathematics
1 answer:
alexira [117]3 years ago
3 0
All you have to do is find the square root of 2601.  You can use the square root key on your calculator or you can do 2601∧1/2
The answer is 51.
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If you are dealt 3 cards from a shuffled deck of 52​ cards, find the probability that all 3 cards are queens.
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If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
What strategy would be the best to solve this problem?
neonofarm [45]

Answer:

32 years old

Step-by-step explanation:

Reverse what the teacher said. Half 120 to get 60. Subtract 28 from 60. The teacher is 32.

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I NEED SOMEONE TO PLS ANSWER THIS I WILL MARK BRAINLYEST IF U ANSWER IT CORRECTLY JUST PLEASE HELP
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1. 24
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I believe these are right, hope this helps!!
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