Ask question

Ask question

All categories

4 years ago

14

the museum's show for July features 30 oil painting by diferent artist. all artists show the same number of paintings and each a

rtist shows more than 1 painting. how many artists could be featured in the show ?type of art : oil painting 30,photographs 24, sketches 21.

1 answer:

Murrr4er [49]4 years ago

5 0

What Your Supposed To Do Is Divide :)

You might be interested in

A right triangle has legs that measure

Anuta_ua [19.1K]

Answer:

15.6 inches

Step-by-step explanation:

10^2 + 12^2 = 244

√244 to the nearest tenth is 15.6

3 0

3 years ago

Express the given situation as a linear inequality. needs at least units of a nutritional supplement per day. Red pills provide

kakasveta [241]

Wiener eejnejene jenejeeb ewj

Jenejeneb Jenner be.

Hope the helps

8 0

3 years ago

What are the possible rational zeros of f(x) = x4 + 2x3 − 3x2 − 4x + 20? (1 point)

Montano1993 [528]

The <u>possible rational zeros</u> of <u>polynomial function</u> $f(x) = x^4 + 2x^3 - 3x^2-4x + 20$ could be only among the <u>divisors</u> of the <u>free term</u> of this polynomial function.

The free term is 20 and the divisors of 20 are:

$\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.$

Answer: correct choice is C

7 0

4 years ago

Enter the value of x. The diagram is not to scale.<br> 680<br> 119°<br> .70

Radda [10]

Answer: 51

119=68+x => x=51

4 0

3 years ago

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago