The surface area of a cylindrical can is equal to the sum of the area of two circles and the body of the cylinder: 2πr2 + 2πrh. volume is equal to π<span>r2h.
V = </span>π<span>r2h = 128 pi
r2h = 128
h = 128/r2
A = </span><span>2πr2 + 2πrh
</span>A = 2πr2 + 2πr*(<span>128/r2)
</span>A = 2πr2 + 256 <span>π / r
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the optimum dimensions is determined by taking the first derivative and equating to zero.
dA = 4 </span>πr - 256 <span>π /r2 = 0
r = 4 cm
h = 8 cm
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Answer:
Check explanation
Step-by-step explanation:
Here, we want to make a prove;
Mathematically , since D is the midpoint of CE
Then;
CE = CD + DE
Also, since D splits the line segment into two equal parts as the midpoint, then CD must be equal to DE
I.e CD = DE
Hence, we can express CE as follows;
CE = DE + DE
CE = 2 DE
Divide both sides by 2
CE/2 = DE
Hence; DE = 1/2 CE
Answer:
x=6,x=-7
Step-by-step explanation:
x^2+x-42=0
x^2-6x+7x-42=0
x(x-6)7(x-6)=0
(x-6)(x+7)=0
Answer:
12
Step-by-step explanation:
(2x-8+2x+10)/2 = 25
(4x+2) = 2×25
4x+2 = 50
4x = 50-2
4x = 48
x = 48/4
x = 12
Answer:
13cm
Step-by-step explanation:
