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3 years ago

The slope of a line passing through H(-2, 5) is -¾. Which ordered pair represents a point on this line?

Mathematics

2 answers:

Gennadij [26K]3 years ago

6 0

Answer:

(6,-1)

Step-by-step explanation:

did it on a test

(performance matters iykyk)

devlian [24]3 years ago

5 0

Y = mx + b
slope(m) = -3/4
(-2,5)...x = -2 and y = 5
now sub and find b, the y int
5 = -3/4(-2) + b
5 = 3/2 + b
5 - 3/2 = b
10/2 - 3/2 = b
7/2 = b

so ur equation is " y = -3/4x + 7/2....or 3x + 4y = 14
now it is just a matter of subbing in ur answer choices to see which ones work.

3x + 4y = 14...subbing in (6,-1)
3(6) + 4(-1) = 14
18 - 4 = 14
14 = 14 (correct).....so (6,-1) is a point on ur line <==

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The equation $T ^ 2 = a ^ 3$ shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?

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To know the factor of aumeto we compared $T_x$ with $T_y$

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$\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x$

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