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3 years ago

Which is the graph of 4x+2y<3?

Mathematics

2 answers:

olchik [2.2K]3 years ago

8 0

Answer:

option B

Step-by-step explanation:

The given inequality is 4x + 2y < 3

2y < 3 - 4x

or $\frac{2y}{2}$

y < (-2x) + $\frac{3}{2}$

Here slope of the line is ( -2 )

So the line will pass through either ( 0, 1.5 ) and ( x, 0 )

Therefore, from the formula of slope

slope = $\frac{y-y'}{x-x'}$

( -2) = $\frac{0-1.5}{x}$

2x = 1.5

x = $\frac{1.5}{2}$

= 0.75

Therefore, points from which this line passes are ( 0, 1.5 ) and ( 0.75, 0 )

Now from the inequality " < " sign denotes that shaded portion will be below on left side of the line.

Therefore, option B will be the answer.

Zina [86]3 years ago

7 0

4x + 2y < 3
2y < -4x + 3
y < -2x + 3/2
y < -2x + 1.5
slope -2 ignore last two choices

if you choose to check (0,0) then
0 < -2(0) + 1.5
0 < 1.5
true so shade side with 0,0

the second graph

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MARKING BRAINLEST HELP ASAP :))))))) SHOW WORK !!

Crazy boy [7]

Answer:

perimeter = 10x + 2

area = 6x^2 + 2x

perimeter = 52

area = 160

Step-by-step explanation:

perimeter = 2 * length + 2 * width

perimeter = 2(3x + 1) + 2(2x)

perimeter = 6x + 2 + 4x

perimeter = 10x + 2

area = length * width

area = (3x + 1)(2x)

area = (2x)(3x + 1)

area = 6x^2 + 2x

For x = 5:

perimeter = 10x + 2 = 10(5) + 2 = 50 + 2 = 52

area = 6x^2 + 2x = 6(5^2) + 2(5) = 6(25) + 10 = 150 + 10 = 160

5 0

4 years ago

Quadrilateral ABCD is inscribed in a circle with angle measures m∠A = (11x − 8)°, m∠B = (3x2 + 1)°, m∠C = (15x + 32)°, and m∠D =

dimulka [17.4K]

Answer:

No for all of the 4 values

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is always 360°, so we have that:

m∠A + m∠B + m∠C + m∠D = 360

11x - 8 + 3x2 + 1 + 15x + 32 + 2x2 - 1 = 360

5x2 + 26x - 320 = 0

Solving the quadratic function using Bhaskara's formula, we have:

Delta = 26^2 + 4*5*320 = 7076

sqrt(Delta) = 84.12

x1 = (-26 + 84.12)/10 = 5.81

x2 = (-26 - 84.12)/10 = -11.01 (this value will generate negative angles, so it is not valid).

Now, finding the angles, we have:

m∠A = 11*5.81 - 8 = 55.91°

m∠B = 3*(5.81)^2 + 1 = 102.27°

m∠C = 15*5.81 + 32 = 119.15°

m∠D = 2*(5.81)^2 - 1 = 66.51°

As all these values are different from the values shown, the answer is No for all of them.

8 0

4 years ago

A survey of 500 farmers showed that of the farmers, 129 grew only wheat, 111 grew only corn, 93 grew only oats, 206 grew wh

yawa3891 [41]

Answer:

a) 419

b)34

c)81

d)52

Step-by-step explanation:

Let x represent the number of farmers who grew all three crops and y represent those who grew corn and oath.

This information is represented on a Venn Diagram as shown in the attachment (A)

Let us add all the regions in wheat and equate to 206.

$206 = 129 + 58 - x + x + 53 - x$

$206 = 240 - x$

$x = 240 - 206 = 34$

We can now add all the regions in corns and equate to 178

$58 - x + x + y + 111 = 178$

$y + 169= 178$

$y = 9$

We redraw the Venn diagram as shown in the attachment (B).

We can now answer the question using the second diagram:

Those who grew at least one of the three crops =exactly one +exactly two +exactly three

=121+111+93+24+9+19+34=419

a) Of the farmers, 419 grew at least one of the three crops.

b) Of the farmers,34 grew all three crops.

c) Of the farmers,81 did not grow any of the three crops.

Exactly two=9+19+24=52

d) Of the farmers, 52 grew exactly two of the three crops.

7 0

4 years ago

Suppose a normal distribution has a mean of 62 and a standard deviation of 4. What is the probability that a data value is betwe

Anon25 [30]

Answer:Given a normal distribution with μ = 62 and σ = 4., calculate the 68-95-99.7 rule, or three-sigma rule, or empirical rule ranges

Calculate Range 1:

Range 1, or the 68% range, states that 68% of the normal distribution values lie within 1 standard deviation of the mean

68% of values are within μ ± σ

μ ± σ = 62 ± 4.

62 - 4. <= 68% of values <= 62 + 4.

58 <= 68% of values <= 66

Calculate Range 2:

Range 2, or the 95% range, states that 95% of the normal distribution values lie within 2 standard deviations of the mean

95% of values are within μ ± 2σ

μ ± 2σ = 62 ± 2(4.)

62 - 2 x 4. <= 95% of values <= 62 + 2 x 4.

62 - 8 <= 95% of values <= 62 + 8

54 <= 95% of values <= 70

Calculate Range 3:

Range 3, or the 99.7% range, states that 99.7% (virtually ALL) of the normal distribution values lie within 3 standard deviations of the mean

99.7% of values are within μ ± 3σ

μ ± 3σ = 62 ± 3(4.)

62 - 3 x 4. <= 99.7% of values <= 62 + 3 x 4.

62 - 12 <= 99.7% of values <= 62 + 12

50 <= 99.7% of values <= 74

Step-by-step explanation:

4 0

3 years ago

What is the area of this composite figure?

MakcuM [25]

Answer:

249cm or the third option

Step-by-step explanation:

I got it right on the test. Good luck to you!

7 0

3 years ago