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exis [7]
3 years ago
6

{y=3-2x. {4x+2y=5. Solve

Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0
No solution because 6 doesnt equal to 5
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An investor buys Rs.1200 worth of share in company first 5 monnths he bought the share at price of Rs.10,12,15,20 and 24 per sha
aleksandrvk [35]

Answer:

14.6

Step-by-step explanation:

The computation of average price paid for the share is shown below:-

Average = \frac{Total\ investment}{Total\ share}

= \frac{6,000}{410}

= 14.6

For more clarification please find the attachment as attached using excel spreadsheet.

By dividing the total investment by the total number of shares we can get the average price paid for the share and the same is to be considered

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4 years ago
9 and 5 twelves, minus 6 and 7 twelves
san4es73 [151]

12*(9+5)-12(6+7)=12
3 0
4 years ago
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Reil [10]
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7 0
4 years ago
What is the simplified form of the following expression?
ziro4ka [17]

For this case we must simplify the following expression:7 (\sqrt [3] {2x}) - 3 (\sqrt [3] {16x}) - 3 (\sqrt [3] {8x})

We rewrite:

16x = 2 ^ 3 * 2x\\8x = 2 ^ 3 * x

We rewrite the expression:

7 (\sqrt [3] {2x}) - 3 (\sqrt [3] {2 ^ 3 * 2x}) - 3 (\sqrt [3] {2 ^ 3 * x}) =

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

Then, taking the terms of the radical:

7 (\sqrt [3] {2x}) - 3 (2 \sqrt [3] {2x}) - 3 (2 \sqrt [3] {x}) =\\7 \sqrt [3] {2x} -6 \sqrt [3] {2x} -6 \sqrt [3] {x} =

We add similar terms:

\sqrt [3] {2x} -6 \sqrt [3] {x}

Answer:

Option C

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umka2103 [35]

Answer:

Step-by-step explanation:

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3. (-2, 3) (0, 0) = (0 - 3)/(0 + 2) = -3/2

4. (1, 1) (3,2) = (2 - 1)/(3 - 1)= 1/2

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