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Andrews [41]
4 years ago
10

Definition: An equation with a degree of 2.

Mathematics
1 answer:
NikAS [45]4 years ago
5 0

Answer:

here's an equation that has a degree of 2

4x^2-37x+19

or

(x+3)(x-1)

=(x^2+2x-3)

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(18,15) and (36,30) whats the slope?
Andre45 [30]

Answer:

5/6

Step-by-step explanation:

Rise over run

y2-y1 / x2-x1

30-15 / 36-18

Hope this helps!

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Find volume PLS HELP
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88.3

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Rita needs to replace the ink cartridge for her printer. She found four brands that make replacement cartridges. The table below
Rasek [7]

The brand of cartridge which is the best buy us the brand with the lowest unit price which is brand A.

<h3>Unit price</h3>

Brand A

Cost = $20

pages = 200

Unit price = $20/200

= $0.1 per page

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Cost = $25

Pages = 125

Unit price = $25/125

= $0.2 per page

Brand C:

Cost = $30

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Unit price = $30 / 150

= $0.2 per page

Brand D:

Cost = $35

Pages = 250

Unit price = $35 / 250

= $0.14 per page

Therefore, the brand of cartridge which is the best buy us the brand with the lowest unit price which is brand A.

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4 0
1 year ago
Divide 18 in two parts so that sum of their reciprocals is 2/5
inn [45]

Answer:

3.6

Step-by-step explanation:

I think that is the answer but im not 100 percent sure

4 0
3 years ago
Solve by quadratic equation​
Ymorist [56]
<h2>Question :</h2>

  • \tt \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}

<h2>Answer :</h2>

  • \large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}

<h2>Explanation :</h2>

\tt : \implies \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}

\tt : \implies \dfrac{(x+2)(x+2) + (x-2)(x-2)}{(x-2)(x+2)} = \dfrac{5}{6}

\tt : \implies \dfrac{(x+2)^{2} + (x-2)^{2}}{(x-2)(x+2)} = \dfrac{5}{6}

<u>Now, we know that</u> :

  • \large \underline{\boxed{\bf{(a+b)^{2} = a^{2} + b^{2}+ 2ab}}}
  • \large \underline{\boxed{\bf{(a-b)^{2} = a^{2} + b^{2} - 2ab}}}
  • \large \underline{\boxed{\bf{(a+b)(a-b) = a^{2} - b^{2}}}}

\tt : \implies \dfrac{x^{2}+2^{2}+ 2 \times x \times 2 + x^{2}+2^{2} - 2 \times x \times 2 }{x^{2}-2^{2}} = \dfrac{5}{6}

\tt : \implies \dfrac{x^{2}+ 4 + \cancel{4x} + x^{2}+ 4 - \cancel{4x}}{x^{2}-4} = \dfrac{5}{6}

\tt : \implies \dfrac{x^{2} + x^{2} + 4 + 4}{x^{2}-4} = \dfrac{5}{6}

\tt : \implies \dfrac{2x^{2} + 8}{x^{2}-4} = \dfrac{5}{6}

<u>By cross multiply</u> :

\tt : \implies (2x^{2} + 8)6= 5(x^{2}-4)

\tt : \implies 12x^{2} + 48 = 5x^{2}-20

\tt : \implies 12x^{2} + 48 - 5x^{2} + 20 = 0

\tt : \implies 7x^{2} + 68 = 0

\tt : \implies 7x^{2} + 0x + 68 = 0

<u>Now, by comparing with ax² + bx + c = 0, we have</u> :

  • a = 7
  • b = 0
  • c = 68

<u>By using quadratic formula</u> :

\large \underline{\boxed{\bf{x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}}}

\tt : \implies x = \dfrac{-(0) \pm \sqrt{(0)^{2} - 4(7)(68)}}{2(7)}

\tt : \implies x = \dfrac{0 \pm \sqrt{0 - 1904}}{14}

\tt : \implies x = \dfrac{\pm \sqrt{- 1904}}{14}

\tt : \implies x = \dfrac{\pm \sqrt{2\times 2\times 2\times 2\times 7\times 17}}{14}

\tt : \implies x = \dfrac{\pm \cancel{2} \times 2\sqrt{7\times 17}}{\cancel{14}}

\tt : \implies x = \dfrac{\pm2\sqrt{119}}{7}

\large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}

Hence value of \bf x =\dfrac{\pm 2\sqrt{119}}{7}

5 0
3 years ago
Read 2 more answers
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