Question

M∠ABC=95° Find m∠ABD and m∠DBC. Please explain how to do this

Answer 1

(2x+23)+(9x-5)=95

11x+18=95

x= 95-18/11

x=7

therefore substituting value of x in the given equations of angles:

angle ABD = 2(7)+23=37°
angle DBC = 9(7)-5= 58° Answer


to verify = 37°+58°= 95° ( which was given)

Answer 2

Answer:

m∠ABD=37° and m∠DBC = 58°.

Step-by-step explanation:

Given information: m∠ABC=95°

From the given figure it is clear that m∠ABD=(2x+23)° and m∠DBC=9x-5° .

$m\angle ABC=m\angle ABD+m\angle DBC$

Substitute value of each angle in the above equation.

$(95)^{\circ}=(2x+23)^{\circ}+(9x-5)^{\circ}$

Comparing the measure we get

$(95)=(2x+23)+(9x-5)$

On combining like terms we get

$95=(2x+9x)+(23-5)$

$95=11x+18$

Subtract 18 from both sides.

$95-18=11x$

$77=11x$

Divide both sides by 11.

$7=x$

The value of x is 7.

$m\angle ABD=(2x+23)^{\circ}=(2(7)+23)^{\circ}=37^{\circ}$

$m\angle DBC=(9x-5)^{\circ}=(9(7)-5)^{\circ}=58^{\circ}$

Therefore m∠ABD=37° and m∠DBC = 58°.

Answer 3

(2x+23)+(9x-5)=95
11x+18=95
x= 95-18/11
x=7
substitute x with 7.
angle ABD = 2(7)+23=37°
angle DBC = 9(7)-5= 58°