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Anvisha [2.4K]
3 years ago
8

Aziza has a triangle with two sides measuring 11 in. And 15 in. She claims that the third side can be any length as long as it i

s greater than 4 in. Which statement about Aziza's claim is correct?
Mathematics
2 answers:
igomit [66]3 years ago
7 0

Answer:

Aziza’s claim is not correct. The third side must be between 4 in. and 26 in.

Step-by-step explanation:

Lelu [443]3 years ago
5 0

Answer:

The third side can be any length as long as it is greater than 4 in and less than 26 in

Step-by-step explanation:

we know that

The<u> Triangle Inequality Theorem</u>, states that The sum of the lengths of any two sides of a triangle is greater than the length of the third side

Let

x ----> the length of the third side

Applying the triangle inequality theorem

1) 11+15 > x

26 > x

rewrite

x < 26 in

2) 11+x > 15

x> 15-11

x > 4 in

therefore

Aziza's claim is incomplete

The third side can be any length as long as it is greater than 4 in and less than 26 in

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Literal Equation

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AnnZ [28]

Answer:

See below.

Step-by-step explanation:

Squaring a number means to multiply the number by itself.

For example, 3^2 means 3 * 3.

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In each case above, you see that the number that is squared is multiplied by itself.

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Now we need to actually multiply -4.5 by -4.5

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4 0
3 years ago
1. If 6 + 3x = 27, what is 2x ?<br> A. 7<br> B. 11<br> C. 14<br> D. 18<br> E. 22
Artemon [7]

Answer:

I don't know what you mean with a b c d and e, but x=7

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8 0
3 years ago
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Lesechka [4]
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0.90a = 44...divide both sides by 0.90
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3 0
3 years ago
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Anit [1.1K]

Answer:

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3 0
3 years ago
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