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slamgirl [31]
3 years ago
9

Helpppppppooo meeee pleaseeeeeeeeeeeeeee help meee

Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0
The piece of wood is in a rectangular prism shape
And the volume formula for a rectangular prism is
  V = length x width x height

The given are
Length = 1, Width = 1, Height = \frac{1}{3}

Apply the formula (substitute the given)

    V = 1 x 1 x\frac{1}{3}

 V of the piece of wood is:  \frac{1}{3} in³

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Val and tony get paid per project. Val is paid a project fee of $44 plus $12 per hour. Tony is paid a project fee of $35 plus $1
Mashutka [201]
12h + 44 = 15h + 35
h= number of hours that Val and Tony work
3 0
2 years ago
If i have a 20 dollar bill and a candy is 4 how many can i buy
8090 [49]

Answer:

a candy is $4

you have a $20 bill

1 candy = 4

2 candies = 8

3 candies = 12

4 candies = 16

5 candies = 20

you can buy 5 candies for $20.

4 0
3 years ago
Read 2 more answers
The mean life of a television set is 119119 months with a standard deviation of 1414 months. If a sample of 7474 televisions is
Pepsi [2]

Answer:

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.6275

What is the probability that the sample mean would differ from the true mean by less than 1.11 months?

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.6275}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.6275}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

3 0
3 years ago
B * In Using the expression above, choose the correct answers for the new balance and the amount of interest earned in the follo
Bad White [126]
In 8 years, you will have $1,573.29 thus $850-$1573.29 = $ <span>723.29 in interest</span>
4 0
2 years ago
Read 2 more answers
Pls help and remember to include the paranthesis
nydimaria [60]
I did this to get 47.5 as the answer not 47 im not sure why but i did (61-7+7×1/2)+17 using the PEMDAS please excuse my dear aunt sally
parenthesis exponents multiply divide add subtract
5 0
2 years ago
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