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damaskus [11]
3 years ago
15

This is related to proportions. in this problem you need to solve for r. The problem is

c%7Br%2B4%7D%7B3%7D%20%5E%7B%7D%20%3D%20-%5Cfrac%20%20%7B10%7D%7B5%7D%20" id="TexFormula1" title="\frac{r+4}{3} ^{} = -\frac {10}{5} " alt="\frac{r+4}{3} ^{} = -\frac {10}{5} " align="absmiddle" class="latex-formula">. Please help me and het 10 points. I really apreciatte it.
Mathematics
1 answer:
Phantasy [73]3 years ago
3 0
<span>8.88≤C≤9.1  and yes i just helped another guy out yours goes too his question too! Bye :)</span>
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Which statement is true regarding the graphed functions?
Paha777 [63]

Answer:

C. f(2) = 0, and g(-2) = 0

Step-by-step Explanation:

From the graph given, the line for f(x) and g(x) intercept each other at x = 0, when y = 4, that is f(0) = 4 and also g(0) = 4.

From the graph, on the line of g(x), when x = -2, y = 0, that is g(-2) = 0.

Also for f(x), when x = 2, y = 0. That is, f(2) = 0.

Therefore, the statement that is true about the graphed function is:

f(2) = 0, and g(-2) = 0

5 0
3 years ago
X+(-4)=-12 Solve the equation and enter the value of x below
Tpy6a [65]

Answer:

x = -8

Step-by-step explanation:

<u>Step 1:  Add 4 to both sides </u>

x + (-4) = -12

x - 4 + 4 = -12 + 4

x = -8

Answer:  x = -8

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3 years ago
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What’s (-3 , 1) reflected over the x-axis
Oxana [17]

Answer: (-3,-1)

Step-by-step explanation:

6 0
3 years ago
Elena collected 431
grandymaker [24]

Answer:

Step-by-step explanation:

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Find the equation for the plane through the points Po(3,-2,5), Qo(-3,-1,-5), and Ro(0,-4,4) The equation of the plane is Type an
Vedmedyk [2.9K]

Answer:

- 21 x + 24 y + 15 z =120

Step-by-step explanation:

Given that

Po(3,-2,5), Qo (-3,-1,-5), and Ro (0,-4,4) ,These are the point in the space.

We know that equation of a plane is given as

\begin{vmatrix}x-x_1 & y-y_1 &z-z_1 \\ x_2-x_1 & y_2-y_1 &z_2-z_1 \\ x_3-x_1 &y_3-y_1  & z_3-z_1\end{vmatrix}=0\\

\begin{vmatrix}x-0 & y+4 &z-4 \\ 3-0 & -2+4 &5-4 \\ -3-0 &-1+4  & -5-4\end{vmatrix}=0.

\begin{vmatrix}x & y+4 &z-4 \\ 3 & 2 &1 \\ -3 &3  & -9\end{vmatrix}=0.

Now by solving above determinate we get

x( -18 -3 ) -(y+4 ) ( -27 +3 ) + ( z- 4) (9+6) = 0

-21 x +24 y -24 x 4 + 15 z - 24 = 0

- 21 x + 24 y + 15 z -120 = 0

- 21 x + 24 y + 15 z =120

Therefore the equation of the plane will be

- 21 x + 24 y + 15 z =120

6 0
3 years ago
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