Attached a solution and showed work.
Answer:
Circumcenter = (4,0)
Circumcircle = √5
Step-by-step explanation:
The circumcentre is the point of intersection of the perpendicular bisectors of a triangle. The vertices of the triangle are equidistant to the circumcentre.
Let us assume the coordinate of the circumcentre is at O(x, y). Therefore the distance between the cirmcumcenter and the vertices are:
AO = BO, therefore
√(x² + y²-4x-2y+5) = √(x² + y² - 10x - 4y + 29)
x² + y²-4x-2y+5 = x² + y² - 10x - 4y + 29
6x + 2y = 24 (1)
BO = CO
√(x² + y² - 10x - 4y + 29) = √(x² + y² - 9x - 8y + 25)
x² + y² - 10x - 4y + 29 = x² + y² - 9x - 8y + 25
-x + 4y = -4 (2)
Multiply equation 2 by 6 and add to equation 1:
26y = 0
y=0
Put y = 0 in -x + 4y = -4
-x + 4(0) = -4
x = 4
The cicumcenter is at (4, 0)
The radius of the circumcircle = AO = BO = CO. Therefore:
19x+12y=17
step 1: move the thing that you're looking for to the left side and all the rest to the right side:
(19x +12y)-19x = 17 -19x
12y = 17 -19x
step 2: to find y, you need to get rid of 12. to do so you need to devide everything by that number:
(12y)/12 = 17/12 -19/12 x
y= 17/12 -19/12 x
step 3: simplify of possible. ( in this exercise it isnt)
step 4: rearange the equation if necessary
y= 17/12 + -19/12x
y= -19/12x + 17/12
Answer:
Step-by-step explanation:
"The octagon has 8 sides and we plug this value into our formula: S = 180(8 - 2) = 1080°. the sum of the measures of the interior angles in an octagon is 1080°. " i found this from google.