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4 years ago

(2x + y)" (10x – 4y)" What is x and y ?

Mathematics

1 answer:

diamong [38]4 years ago

5 0

Answer:

20x²+2xy-4y²

Step-by-step explanation:

(2x + y) (10x -4y)

=2x (10x-4y) +y (10x-4y)

= 20x²-8xy+10xy-4y²

=20x²+2xy-4y²

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Please answer asap for brainlist

castortr0y [4]

Table m I believe because each x has one y

8 0

3 years ago

Use the Chain Rule to find the indicated partial derivatives. u = x2 + yz, x = pr cos(θ), y = pr sin(θ), z = p + r; (partial u)/

devlian [24]

$u(x,y,z)=x^2+yz$

$\begin{cases}x(p,r,\theta)=pr\cos\theta\\y(p,r,\theta)=pr\sin\theta\\z(p,r,\theta)=p+r\end{cases}$

At the point $(p,r,\theta)=(2,2,0)$ , we have

$\begin{cases}x(2,2,0)=4\\y(2,2,0)=0\\z(2,2,0)=4\end{cases}$

Denote by $f_x:=\dfrac{\partial f}{\partial x}$ the partial derivative of a function $f$ with respect to the variable $x$ . We have

$\begin{cases}u_x=2x\\u_y=z\\u_z=y\end{cases}$

The Jacobian is

$\begin{bmatrix}x_p&x_r&x_\theta\\y_p&y_r&y_\theta\\z_p&z_r&z_\theta\end{bmatrix}=\begin{bmatrix}r\cos\theta&p\cos\theta&-pr\sin\theta\\r\sin\theta&p\sin\theta&pr\cos\theta\\1&1&0\end{bmatrix}$

By the chain rule,

$u_p=u_xx_p+u_yy_p+u_zz_p=2xr\cos\theta+zr\sin\theta+y$

$u_p(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_p(2,2,0)=16}$

$u_r=u_xx_r+u_yy_r+u_zz_r=2xp\cos\theta+zp\sin\theta+y$

$u_r(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_r(2,2,0)=16}$

$u_\theta=u_xx_\theta+u_yy_\theta+u_zz_\theta=-2xpr\sin\theta+zpr\cos\theta$

$u_\theta(2,2,0)=-2\cdot4\cdot2\cdot2\sin0+4\cdot2\cdot2\cos0\implies\boxed{u_\theta(2,2,0)=16}$

7 0

3 years ago

Help i need help with this problem

Cloud [144]

Answer:

<em>Natalie's total spread = 18</em>

Step-by-step explanation:

The 'spread' of a crossword puzzle tournament player is computed as his/her total score minus the opponent's total score.

Natalie's scores are:

N=410+380+395+370+320+360=2,235

Opponent's scores are:

O=395+360+412+355+340+355=2,217

Natalie's total spread = 2,235 - 2,217 = +18

Natalie's total spread = 18

4 0

3 years ago

Pls help I don’t understand

alina1380 [7]

That is all the work needed to solve this problem

8 0

3 years ago

2. A 48-foot rope is cut into three lengths. The second length of rope is twice the first

BigorU [14]

Answer:

48/3.2=15

Got 3.2 from Second length is twice the third so we divide by 2 + 1 = 3

0.2 is from 1/5 = 0.2

3 is the third length

30 is second length and 15 is the first.

Step-by-step explanation:

5 0

3 years ago