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Degger [83]
3 years ago
5

A square has a side of length of 12 centimeters. Which of he following is closest to the length of a diagonal of the square?

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0
<span>length of a diagonal of the square = </span>√(12^2 + 12^2)
= √(144 + 144)
= √288
= 16.97 cm
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Please help with the questions in the image
polet [3.4K]

Answer:

  • (a) C(d) = 270 + 0.20d
  • (b) C(1800) = 630
  • (c) see attached (lower right graph). The slope represents the cost (in dollars) per mile.
  • (d) It represents the fixed cost (amount she pays even if she does not drive)
  • (e) the cost increases as the number of miles driven increases

Step-by-step explanation:

(a) You are given two points, (d, C) = (360, 342) and (780, 426). The two-point form of the equation for a line can be helpful.

... y = (y2 -y1)/(x2 -x1)(x -x1) +y1

Using the given points and variables, ...

... C = (426 -342)/(780 -360)(d -360) +342

... C = (84/420)(d -360) +342

... C = 0.20d +270 . . . . the equation for cost as a function of miles driven

(b) Fill in the value for d and do the arithmetic.

... C = 0.20·1800 +270 = 360 +270 = 630

(c) The slope of the curve is (change in dollars)/(change in miles) = $/mile, the cost of each mile driven. (It is $0.20 per mile.)

(d) The C-intercept is C(0) = cost for 0 miles driven. (It is $270.)

(e) Both your own experience and the problem statement tell you that the cost of vehicle operation varies with miles driven. If nothing else, you need to pay more for gas the farther you drive.

(In real life, you don't expect the model to be exactly linear, becasue you get a large jump in cost when you reach certain maintenance interval miles: 15,000, 30,000, and so on.)

7 0
3 years ago
I need help, please. it would mean a lot I need it now
fomenos

Answer:

60 feet

Step-by-step explanation:

a - 2x

b - x

c - 3x

120/6 = 20

20 x 3 = 60

8 0
3 years ago
Read 2 more answers
A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
These two polygons are similar. ​
Nady [450]

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yea........ hi how you doinn

4 0
3 years ago
Please help i will give brainliest to right answer (it’s multiple answers
liberstina [14]

Answer:

b c e

Step-by-step explanation:

7 0
3 years ago
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