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vovikov84 [41]
2 years ago
15

A triangle has three different integer side lengths and a perimeter of 20 units. What is the max length of any one side?

Mathematics
1 answer:
Troyanec [42]2 years ago
3 0
X + x+1 + x + 2 = 20
3x + 3 = 20
3x = 17 but can't start with x = 6 because 6+7+8 > 20,
so have start with 5 + 6 + 7 = 18 are the 3 sides.
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This figure consists of a rectangle and a quarter circle. What is the perimeter of this figure? Use 3.14 for pi.
Ghella [55]

The area of the given shape is 220.24 square cm.

Step-by-step explanation:

Step 1;

Area of given shape = Area of the rectangle + Area of the quarter circle.

The given rectangle measures a length of 17 cm and a width of 10 cm. The area of any given rectangle is the multiplication of its length and width. Area of the Rectangle = Length * Width = 17 cm * 10 cm = 170 square cm.

The area of any given circle is π times the square of the radius. The radius of this circle is equal to 8 cm.

Area of the circle = π × r² = 3.14 × 8 × 8 = 200.96 square cm.

200.96 square cm is the area of a full circle with a radius of 8 cm. We divide the area by 4 to convert it into a quarter-circle.

Area of the quarter circle = 200.96 square cm / 4 = 50.24 square cm.

So the quarter circle covers an area of 50.24 square cm.

Step 2;

Area of given shape = Area of the rectangle + Area of the quarter circle

Area of given shape = 170 + 50.24 = 220.24 square cm.

5 0
3 years ago
Could someone pls explain this step by step? Really simplify it pls because I don't understand it at all.
Lunna [17]

Answer:

  • y = 2x -6
  • y = -x +2
  • y = 4/5x -2
  • y = -3/2x +4

Step-by-step explanation:

The slope-intercept form of the equation for a line is ...

  y = mx +b . . . . . where m is the slope, and b is the y-intercept

For these equations, writing them in slope-intercept form means "solve for y." You always do any "solve for ..." problem by undoing the operations that are done to the variable. Addition is undone by adding the opposite. Multiplication is undone by division.

As always, whatever operation we perform on one side of the equal sign must also be performed on the other side. That is how the equal sign remains valid.

__

<h3>a)</h3>

  1/2y = x -3

All we need to do is get rid of the coefficient of y. We can do that by dividing by 1/2, or multiplying by 2. The latter is easier to see, perhaps.

 2(1/2y) = 2(x -3)

  y = 2x +2(-3)

  y = 2x -6

__

<h3>b)</h3>

  x +y = 2

Here, we need to undo the addition of x. We do that by adding (-x) to both sides of the equation.

  -x +x +y = -x +2

  y = -x +2

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<h3>c)</h3>

  4x -5y -10 = 0

This is a combination of the above operations. We can separate the y-term from the others by either subtracting the others, or adding the opposite of the y-term. We choose the latter, because that will give a positive coefficient for y. Adding 5y to both sides gives ...

  4x -5y +5y -10 = 5y

  5y = 4x -10 . . . . . . . . simplify and put y on the left

Now, we need to divide by the coefficient of y. We do that to both sides of the equation.

  5y/5 = (4x -10)/5

  y = 4/5x -10/5

  y = 4/5x -2

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<h3>d)</h3>

  3x = -2y +8

We have a constant with the y-term. To get rid of it, we add its opposite to both sides.

  3x -8 = -2y +8 -8

  3x -8 = -2y

As before, we divide by the coefficient of y:

  (3x -8)/(-2) = (-2y)/(-2)

  -3/2x +4 = y

  y = -3/2x +4

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