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puteri [66]
4 years ago
10

how do you write the equation of a line with a slope of -2/15 that passes through the point ( - 5,5 )

Mathematics
2 answers:
prohojiy [21]4 years ago
8 0

point slope form

y-y1 = m(x-x1)

y-5 = -2/15(x--5)

y-5 = -2/15 (x+5)

change to slope intercept form

distribute

y-5 =-2/15x -10/15

y-5 = -2/15x -2/3

add 5 to each side

y = -2/15x -2/3 + 5

y = -2/15x -2/3 + 15/3

y = -2/15x +13/3

svetoff [14.1K]4 years ago
3 0
A lines equation is generally

mx+b

where m is the slope (-2/15)
and b is the y intercept

point: (-5,5)

y = mx +/- b

5 = -2/15 - 5 (plugging in)

multiply b by the numerator

5 = 10/15

multiply y by the denomenator

75/15 - 10/15

subtract ^

65/15 (4.33 when calculated)
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PLEASE ANSWER + BRAINLIEST!!!!
kupik [55]
So, let's begin...
First off, you must note that the question is asking for the d value when you substitute the value of c(x).
You are given the following information:
1. The c(x) value is already given to be 0.75x.
2. The equation to find d of (any value) is 0.8y-5.

So, substitute the value of 0.75x as a y value into 0.8y - 5. This is because you are substituting the value of c(x) for d. This is equal to 0.8 times 0.75x - 5. This is equal to 0.6x - 5, which is the function. Thus, your final answer is d(c(x)) = 0.6x - 5.
If you have any questions please comment. Otherwise, hope this helps! :)
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<em>Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!</em>

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