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puteri [66]
4 years ago
10

how do you write the equation of a line with a slope of -2/15 that passes through the point ( - 5,5 )

Mathematics
2 answers:
prohojiy [21]4 years ago
8 0

point slope form

y-y1 = m(x-x1)

y-5 = -2/15(x--5)

y-5 = -2/15 (x+5)

change to slope intercept form

distribute

y-5 =-2/15x -10/15

y-5 = -2/15x -2/3

add 5 to each side

y = -2/15x -2/3 + 5

y = -2/15x -2/3 + 15/3

y = -2/15x +13/3

svetoff [14.1K]4 years ago
3 0
A lines equation is generally

mx+b

where m is the slope (-2/15)
and b is the y intercept

point: (-5,5)

y = mx +/- b

5 = -2/15 - 5 (plugging in)

multiply b by the numerator

5 = 10/15

multiply y by the denomenator

75/15 - 10/15

subtract ^

65/15 (4.33 when calculated)
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Answer:

See explanation

Step-by-step explanation:

Let x be the number of hours per week Nando is brisk walking  and y be the number of hours per week Nando is  biking at a moderate pace.

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x+y\le 5

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You get the system of two inequalities:

\left\{\begin{array}{l}x+y\le 5\\ 350x+700y\ge 2,000\end{array}\right.

The attached graph shows the solution set to this system of inequalities. In this diagram, red region represents the solution set to the first inequality, blue region represents the solution set to the second inequality and their intersection is the solution set to the system of two inequalities.

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3 years ago
Lemon drops and jelly beans are mixed to make a 100 pound mix. if the lemon drops cost $1.90 per pound and jelly beans cost $1.2
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L = lemon drops

J = jelly beans

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40 pounds of Lemon Drops are needed

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4 years ago
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