how do you write the equation of a line with a slope of -2/15 that passes through the point ( - 5,5 )
2 answers:
point slope form
y-y1 = m(x-x1)
y-5 = -2/15(x--5)
y-5 = -2/15 (x+5)
change to slope intercept form
distribute
y-5 =-2/15x -10/15
y-5 = -2/15x -2/3
add 5 to each side
y = -2/15x -2/3 + 5
y = -2/15x -2/3 + 15/3
y = -2/15x +13/3
A lines equation is generally
mx+b
where m is the slope (-2/15)
and b is the y intercept
point: (-5,5)
y = mx +/- b
5 = -2/15 - 5 (plugging in)
multiply b by the numerator
5 = 10/15
multiply y by the denomenator
75/15 - 10/15
subtract ^
65/15 (4.33 when calculated)
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