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ahrayia [7]
3 years ago
5

Which ordered pair Is a solution of 2y-3x=8

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0
(2,7)

(2*7)-(3*2)=8
14-6=8
You might be interested in
A car travels at an average speed of 50 km/h for 1.5 hours. How far did the car travel in km?
boyakko [2]

Answer:

75 km

Step-by-step explanation:

(50km/h)(1.5h) =<em> 75km</em>

7 0
2 years ago
URGENT!!! 50 POINTS!!! URGENT!!!!!!! Consider the polynomial functions P (x) and Q (x)​ , where neither polynomial is a constant
Nutka1998 [239]

Answer:

Always

Always

Sometimes

Never

Step-by-step explanation:

P(X) + Q(X)

Sum of two polynomials is always a polynomial.

For example, Let P(x) = 3x² and Q(x) = 5x

$ \implies P(x) + Q(x) = 3x² + 5x

This is again a polynomial.

In other words, we can say that Polynomial is closed under addition.

P(x) . Q(x)

Product of two polynomials is again a polynomial.

Let P(x) = 2x and Q(x) = a constant function, 5

Then the product = 10x, is again a polynomial.

Multiplication of two polynomials is closed.

P(x) / Q(x)

This need not always be a polynomial. When Q(x) = a constant function zero, i.e., Q(x) = 0, then the function is not defined.

But let's say P(x) = 5x² and Q(x) = x.

$ \frac{P(x)}{Q(x)} $ = $ \frac{5x^2}{x} $ = 5x, a polynomial.

So, $ \frac{P(x)}{Q(x)} $ is a polynomial sometimes.

We can, say Division is not always closed.

1/Q(x)

This could never be a polynomial. This is not even in the form of a polynomial. So, $ \frac{1}{Q(x)} $ is never a polynomial.

Hence, the answer.

7 0
3 years ago
The amount of time required for an investment to generate
n200080 [17]
It is called the payback period
3 0
3 years ago
Factor the greatest common binomial factor from each polynomial
sladkih [1.3K]
Answer:
(5x-1)(6x^2+1)

Solution:
6x^2(5x-1)+5x-1
=30x^3-6x^2+5x-1
=(30x^3-6x^2) + (5x-1)
=6x^2(5x-1)+(5x-1)
=(5x-1)(6x^2+1)

HOPE THIS HELPS!
4 0
2 years ago
Tyler's mom purchased a savings bond for Tyler. The value of the savings bond increases by 4% each year. One year after it was p
Alla [95]

Answer:

150

Step-by-step explanation:

Since the value of the bond increases by 4% each year and only 1 year passed by then the ROI is not compounded and we only need to find the value before the 4% was implemented. In order to add 4% to a value we would multiply that value by 1.04 which increases that value by 4%. So, to find the value before the interest was added we would need to divide the new value by 1.04 instead.

$156 / 1.04 = $150

Finally, we can see that the value of the bond when Tyler's mom purchased it was 150

6 0
3 years ago
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