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ahrayia [7]
3 years ago
5

Which ordered pair Is a solution of 2y-3x=8

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0
(2,7)

(2*7)-(3*2)=8
14-6=8
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Domain and range of graph need ASAP
Lostsunrise [7]

Answer:

Domain: -6 \leq x \leq 3

Range: -3 \leq x \leq 6

Step-by-step explanation:

The domain is the set of real values which can be inputted into a function and produce a real output. In this case, the domain is the following: -6 \leq x \leq 3, because this is the set of real values for which the function will produce a real output.

The range is the set of real values which a function outputs when a value from the domain is entered into the function. This is the set of y-values that one can see on the graph, the possible y-values are in between (-3) and (6).

6 0
2 years ago
The SAT mathematics scores in the state of Florida for this year are approximately normally distributed with a mean of 500 and a
creativ13 [48]
99.7%

This is because the likelihood of a point being within 2 SDs of the mean is 99.7%. 
7 0
3 years ago
Simplify-2(y+4) + 3y
Pie

Answer: y-8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Add up the answer first to see of these correct or incorrect, if incorrect explain why it is not equal.
Stells [14]

Answer:

1) incorrect

2) incorrect

Step-by-step explanation:

-2x-2x = 0 ?

-2x -2x = -4x

It will be 0 only if x = 0.

Not always true, so incorrect

x+x = x² ?

2x = x²

They will be equal if x = 0 or 2.

Not always true so incorrect

8 0
3 years ago
Use linear approximation to estimate f (2.85 )given that f (3 )equals 2 and f prime (3 )equals 5.
Allisa [31]

Answer:

Step-by-step explanation:

Given that,

f(3) = 2

f'(3) = 5.

We want to estimate f(2.85)

The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".

At x = a, y = f(a) and the slope of the tangent line is f'(a).

So, in point slope form, the tangent line has equation

y − f(a) = f'(a)(x − a)

The linearization solves for y by adding f(a) to both sides

f(x) = f(a) + f'(a)(x − a).

Given that,

f(3) = 2,

f'(3) = 5

a = 3, we want to find f(2.85)

x = 2.85

Therefore,

f(x) = f(a) + f'(a)(x − a)

f(2.85) = 2 + 5(2.85 - 3)

f(2.85) = 2 + 5×-0.15

f(2.85) = 2 - 0.75

f(2.85) = 1.25

5 0
3 years ago
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