Answer:
The range of crying times within 68% of the data is (5.9, 8.1).
The range of crying times within 95% of the data is (4.8, 9.2).
The range of crying times within 99.7% of the data is (3.7, 10.3).
Step-by-step explanation:
According to the Empirical Rule in a normal distribution with mean µ and standard deviation σ, nearly all the data will fall within 3 standard deviations of the mean. The empirical rule can be broken into three parts:
- 68% data falls within 1 standard deviation of the mean. That is P (µ - σ ≤ X ≤ µ + σ) = 0.68.
- 95% data falls within 2 standard deviations of the mean. That is P (µ - 2σ ≤ X ≤ µ + 2σ) = 0.95.
- 99.7% data falls within 3 standard deviations of the mean. That is P (µ - 3σ ≤ X ≤ µ + 3σ) = 0.997.
The mean and standard deviation are:
µ = 7
σ = 1.1
Compute the range of crying times within 68% of the data as follows:

The range of crying times within 68% of the data is (5.9, 8.1).
Compute the range of crying times within 95% of the data as follows:

The range of crying times within 95% of the data is (4.8, 9.2).
Compute the range of crying times within 99.7% of the data as follows:

The range of crying times within 99.7% of the data is (3.7, 10.3).
A) 100 • 3 • x
b) 100 + 2100 = 2,200 in one week
c) 300 • 30 = 9,000 + 100 = 9,100 in a month with 30 days
Answer:
Ans 2
Step by step explanation :
2 X 1 = 2
Hello, the answer is simple it is W=6
Answer:
-7
Step-by-step explanation:
(7 4/9 −8)∙3.6–1.6∙( 1/8 − 3/4 )+1 2/5 ÷(−0.35)
PEMDAS, parenthesis
-5/9∙3.6–1.6∙(1/8-6/8)+1 2/5 ÷(−0.35)
PEMDAS, division
-5/9∙3.6–1.6∙-5/8-4
PEMDAS, multiplication
-5/9∙ 18/5– 8/5 ∙-5/8-4
-2-1-4
PEMDAS, subtraction
-7
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