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rodikova [14]
4 years ago
13

Suppose that you are taking a multiple-choice exam with five questions, each have five choices, and one of them is correct. Beca

use you have no more time left, you cannot read the question and you decide to select your choices at random for each question. Assuming this is a binomial experiment, calculate the binomial probability of obtaining exactly three correct answers.
Mathematics
1 answer:
BabaBlast [244]4 years ago
5 0

Answer:

0.051

Step-by-step explanation:

Each question has five choices.

So , probability of correct answer is 1/5 i.e.0.2

p = 5  

Total number of questions = 5

n = 5

Let X be the number of questions that are correctly answered.  

X follows Binomial(5 , 0.2)

Using binomial probability formula ,

P(X = x) = (ₙ C ₓ) * pˣ * (1 - p)ⁿ₋ˣ ; x = 0 ,1 , 2 , ....., n

Find P (Exactly 3)

= P(X = 3)  

=  (₅C ₃) * 0.2³ * (1 - 0.2)⁵ ⁻ ³

= (₅ C ₃) * 0.2³ * (1 - 0.2)²

= 0.051

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kirza4 [7]

Answer:

89.86\times 10^6

Step-by-step explanation:

9.3\times 10^7 - 3.14\times 10^6\\

In order to simplify the above expressions we make sure that we get same powers of 10 for both the terms.

So, we multiply and divide the first term with 10

Dividing first term by 10.

\frac{9.3\times 10^7}{10}\\9.3\times 10^{7-1}\\9.3\times 10^6\\

Now multiplying it by 10.

10\times9.3\times 10^6\\93\times 10^6

Evaluating the new expressions.

93\times 10^6 - 3.14\times 10^6\\

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5 0
3 years ago
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

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3 years ago
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Plzzzz somebody help me right away
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Well if you know what the area of the rectangle is and the width then you would have to divide area of the rectangle by the width.

24,396 / 38 = 642

The length is 642 centimeters.

Hope this helps!

5 0
3 years ago
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