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Ber [7]
3 years ago
7

Why do you end up with 2 every time?

Mathematics
1 answer:
Andrej [43]3 years ago
8 0
Evaluate the expression form of the instructions.

(((3x-4)*2+20)/6)-x

Distribute the 2
((6x-8+20)/6)-x

Combine like terms
(6x+12)/6-x

Divide by 6
x+2-x

Add and subtract
2

Final answer: 2
Explanation: When you simplify the expression using the order of operations, the numbers cancel each other out. The variable x, is also cancelled out and the only remaining constant is 2.
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Clarissa has a budget of $1,200 a month to spend for rent and food. She has already spent $928 this month. Which inequality repr
shtirl [24]

Answer:

1200-928 = 272 for the rest of the month Clarissa has to spend.

Step-by-step explanation:

So we don't want her to go over her budget so we wouldn't choose a greater than option for her so eliminate the first option and the last option. Now we just have the middle two. We want to keep it under 1200 but theres nothing wrong with spending that exact amount each month so I would pick x less than or equal to 272, since we can still equal the total of less than the total and not go over. Option 2 or B.

6 0
3 years ago
Read 2 more answers
What is -4+(-8+j)= simplified
fgiga [73]

Answer:

Step-by-step explanation:

−4−8+j

=−4+−8+j

Combine Like Terms:

=−4+−8+j

=(j)+(−4+−8)

=j+−12

Answer:

=j−12

6 0
3 years ago
PLS SOLVE AND EXPLAIN
Sonja [21]
The answer to the question

6 0
3 years ago
Evaluate the expression,<br> 32 +6*22-42=23
kupik [55]

Answer:

d

Step-by-step explanation:

4 0
3 years ago
a ladder 5 meters long is leaning against a wall. the base of the ladder is sliding away from the wall at a rate of 1 meter per
Kruka [31]

Complete question :

a ladder 5 meters long is leaning against a wall. the base of the ladder is sliding away from the wall at a rate of 1 meter per second. how fast is the top of the ladder sliding down the wall at the instant when the base is 4 meters from the wall?

Answer:

-4/3 m/s

Step-by-step explanation:

Using Pythagoras :

a² = x² + c²

5² = x² + y² - - - (1)

The horizontal distance x with respect to time t = 1m/sec

dx/dt = 1m/sec

To obtain the vertical height 'y' with respect to time t when x = 4

5² = x² + y²

Wen x = 4

5² = 4² + y²

25 = 16 + y²

y =√(25 - 16)

y = 3

Differentiate (1) with respect to t

x² + y² = 25 - ---- - (1)

2x * dx /dt + 2y dy/dt = 0

dx/dt = 1

x = 4.

y = 3

2(4)(1) + 2(3) * dy/dt = 0

8 + 6dy/dt = 0

6 dy/dt = - 8

dy/dt = - 8/6

dy/dt = - 4/3

8 0
3 years ago
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