First, we need her speed as it will serve as the slope of the equation.
Distance = 2 km
time = 18 min
Speed = 1/9 km/min
k = (1/9)t
Where k is the distance in km and t is the time in minutes.
Answer
y=−3/5x−23/5
given the slope m of a line then the slope of a line
perpendicular to it is
Y² + 8y - 33 :
Break the expression into groups for formula ax²+ bx+c :
= (y²- 3y) + (11y - 33 )
Factor y from y² - 3y => y (y - 3)
Factor out 11 from 11 y - 33 => 11 (y - 3)
= y ( y- 3 ) + 11 ( y - 3 )
Factor out common term (y - 3 ) :
= ( y - 3 ) ( y + 11 )
hope this helps!
