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miv72 [106K]
3 years ago
13

6.4=0.8m solve for m

Mathematics
2 answers:
jeyben [28]3 years ago
4 0
6.4 = 0.8m
/0.8    /0.8
    8 = m
ExtremeBDS [4]3 years ago
4 0
We want to isolate m so you find the value of it. To bring it over the equal sign and keep the equation even you simply do the opposite of it's current state (a value next to a letter always multiplies so you have to divide bringing it over the = sign).

6.4/0.8=m so m=8

Hope this helps and was easy to understand so you can do it on your own in the future.
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Answer:

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Step-by-step explanation:

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In January, Wally's Widget World had sales of $12,500 and expenses of $10,200. The profit for January was _____.
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Read 2 more answers
The sketch shows the distance three runners travel during a race. Describe what occurs at times A,B,C and D. In what order do th
goldfiish [28.3K]

Answer:

Notice that the distance is in the y-axis, and the time in the x-axis.

First, let's see what happens in the four points:

A) You can see that in point A, the steepness of the line increases, this means that the speed of the runner increases in that point.

B) In this point, the runner that increased his/her speed in point A crosses the graph of another runner, this means that they are at the same distance to the end and at the same time.

C) In this point again two runners are at the same distance and the same time, and we also can see that the runer that increased his/her speed at point A, now has reached the end of the race (because his line stops increasing, wich means that he/she already finished the race)

D) The las runner finishes the race at point D.

Then the first runner that finishes the race is the one with the shorter graph (shorter graph means that he ran for less time than the others, wich means that he/she finished first)

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6 0
3 years ago
Plz help<br>urgent !!!!<br>will give the brainliest !!​
Mkey [24]

Answer:

X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}

Step-by-step explanation:

The question we have at hand is, in other words,

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix} - where we have to solve for the value of X

If we have to isolate X here, then we would have to take the inverse of the following matrix ...

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix} ... so that it should be as follows ... \begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}

Therefore, we can conclude that the equation as to solve for " X " will be the following,

X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} - First find the 2 x 2 matrix inverse of the first portion,

\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1} = \frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}= \frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix} = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} ,

X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix} - Simplifying this, we should get ...

\begin{bmatrix}1&3\\ 2&4\end{bmatrix} ... which is our solution.

7 0
3 years ago
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