Question

Find the value of y if B is between A and C, AB is 2y, BC is 6y, and AC is 48.

Answer 1

Answer:

7. C. 6

8. H. √34

9. A. (1, 3.5)

10. J. 10

Step-by-step explanation:

7. AB = 2y, BC = 6y, AC = 48

AB + BC = AC (segment addition theorem)

Substitute the above values into the equation

2y + 6y = 48

Solve for y

8y = 48

Divide both sides by 8

8y/8 = 48/8

y = 6

8. Distance between P(2, 8) and Q(5, 3):

$PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$P(2, 8) = (x_1, y_1)$

$Q(5, 3) = (x_2, y_2)$

$PQ = \sqrt{(5 - 2)^2 + (3 - 8)^2}$

$PQ = \sqrt{(3)^2 + (-5)^2}$

$PQ = \sqrt{9 + 25}$

$PQ = \sqrt{34}$

9. Midpoint (M) of segment LB, for L(8, 5) and B(-6, 2) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $L(8, 5) = (x_1, y_1)$

$B(-6, 2) = (x_2, y_2)$

Thus:

$M(\frac{8 + (-6)}{2}, \frac{5 + 2}{2})$

$M(\frac{2}{2}, \frac{7}{2})$

$M(1, 3.5)$

10. M = -10, N = -20

Distance between M and N, MN = |-20 - (-10)|

= |-20 + 10| = |-10|

MN = 10