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olya-2409 [2.1K]
4 years ago
13

What is the corresponding value at the given point x=3

Mathematics
1 answer:
GrogVix [38]4 years ago
8 0
The answer of above question is y = 5
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On the first half of a birdwatching trip, Marya saw 8 birds, and 25% were cardinals. By the end of the trip, she had seen 12 mor
Vinvika [58]

Answer:

10% of all the birds she saw were cardinals.

Step-by-step explanation:

25% of 8 is 2

So she saw 2 cardinal birds overall.

12+8=20

2 0f 20 is 10%

Hope this helps. Have a nice day!

3 0
3 years ago
A bottle of ketchup holds .946 liters. How many milliliters of ketchup are in the bottle?
just olya [345]
Recall that, in the metric system, there are 1000 milliliters in one liter, so all you need to do is multiply .946 by one thousand. This is expressed by moving the decimal point three places to the right.

This gives us 946 milliliters as the answer.

Hope this helps!
3 0
3 years ago
What is the v?<br> -18 - 3/4v = 3
lesantik [10]

Step-by-step explanation:

- 18 -  \frac{3}{4v}  = 3

-  \frac{3}{4v}  = 3 + 18

-  \frac{3}{4v}  = 21

Now doing cross multiply

-3 = 21 * 4v

v = -   \frac{3}{21 \times 4}

Therefore

v \:  =  \frac{1}{28}

Hope this helps.

8 0
3 years ago
Read 2 more answers
Please help ASAP I’ll give brainliest
butalik [34]
Write the equations in matrix,

\left[\begin{array}{ccc}5&-1&1\\1&2&-1\\2&3&-3\end{array}\right]   \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =   \left[\begin{array}{ccc}4\\5\\5\end{array}\right]

Using row transformation,
R₂ <---> R₃ 

\left[\begin{array}{ccc}5&-1&1\\2&3&-3\\1&2&-1\end{array}\right]   \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =  \left[\begin{array}{ccc}4\\5\\5\end{array}\right]

Using,
R₂ ---> R₂ - 2R₃

\left[\begin{array}{ccc}5&-1&1\\0&-1&-1\\1&2&-1\end{array}\right]   \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =   \left[\begin{array}{ccc}4\\-5\\5\end{array}\right]

Using,
R₂ --- > (-1)R₂

\left[\begin{array}{ccc}5&-1&1\\0&1&1\\1&2&-1\end{array}\right]   \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =   \left[\begin{array}{ccc}4\\5\\5\end{array}\right]

Using row transformation,
R₂ <----> R₃
\left[\begin{array}{ccc}5&-1&1\\1&2&-1\\0&1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}4\\5\\5\end{array}\right]

Using,
R₂ ---> R₂ - R₁/5

\left[\begin{array}{ccc}5&-1&1\\0&11/5&-6/5\\0&1&1\end{array}\right]   \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =   \left[\begin{array}{ccc}4\\21/5\\5\end{array}\right]

Using,
R₃ ---> R₃ - 5R₂/11 

\left[\begin{array}{ccc}5&-1&1\\0&11/5&-6/5\\0&0&17/11\end{array}\right]   \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =   \left[\begin{array}{ccc}4\\21/5\\34/11\end{array}\right]

∴ 5x-y+z = 4 ====(i)
   11y-6z = 21 === (ii)
    17z=34 === (iii)

from iii,
z=2.
Plug z=2 in ii to get y, 
∴y=3.
Plug y and z values in i to get x,
∴x=1

Therefore the solution to the system of equations is (1,3,2)
3 0
3 years ago
True or False. Is (3,1) a solution to this system:
Alisiya [41]

It would be false since none of them are equal to 1.

8 0
4 years ago
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