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Igoryamba
3 years ago
10

the area of a room is 96 square feet. The length is (x+1) feet and the width is (x-3) feet. find the dimensions of the room

Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

length = 12 feet and width = 8 feet

Step-by-step explanation:

since the area = 96 ft² then

(x + 1)(x - 3) = 96 ( A = lw )

expand the factors on the left side

x² - 2x - 3 = 96 ( subtract 96 from both sides )

x² - 2x - 99 = 0 ← in standard form

(x - 11)(x + 9) = 0 ← in factored form

equate each factor to zero and solve for x

x - 11 = 0 ⇒ x = 11

x + 9 = 0 ⇒ x = - 9

but x > 0 ⇒ x = 11

length = 11 + 1 = 12 feet and width = 11 - 3 = 8 feet


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Step-by-step explanation:

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3 years ago
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weeeeeb [17]
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6 0
4 years ago
A rectangular box which is open at the top can be made from an12-by-18-inch piece of metal by cutting a square from each corner
algol [13]

Answer:

h=2.35in, l=13.3in and w=7.3in

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram that will represent the prolem. (Look at attached picture)

From the diagram we can see that the length ad the width of the box are found by  using the following expressions:

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W= 12-2x

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next, we can make use of the volume formula of a rectangular prism, which is the following:

V=WLH

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and for ease of calculation, we can multiply the terms, so we get:

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and now we can solve. We can start by factoring the left side of the equation, so we get:

12(x^{2}-10x+18)=0

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x^{2}-10x+18=0

This one can only be solved by using the quadratic formula:

x=\frac{-b\pm \sqrt{-b^{2}-4ac}}{2a}

so we substitute the corresponding values:

x=\frac{-(-10)\pm \sqrt{-(-10)^{2}-4(1)(18)}}{2(1)}

which yields:

x=7.65in or x=2.35in

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So the 2.35in height would give us the greatest box. Now we can use it to find the height, the width and the length of the box.

Height=x=2.35

W=12-2x=12-2*2.35=7.3in

L=18-2x=18-2(2.35)=13.3in

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3 years ago
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