The complex conjugate of 13-21i is 1.3+ 2i.
In general the conjugate of a+bi is a - bi
and the conjugate of a-bi is a + bi
Answer:
15. Area of parallelogram = bh
b = 9m
h = 4m
a = 9*4 = 36m^2
You can also use the rectangle property here.
a = l*b
l = 9
b = 6
a = 9*6 = 54 m^2
Though I would prefer the first one better.
16. Area of triangle = 1/2*bh
b = 17m
h = 3
a = 17*3/2 = 51/2 = 25.5m^2
18. Area of a trapezium = a+b/2*h (a and b are two parallel sides and h the height)
a = 15
b = 7
h = 15
a = 15+7/2*15 = 22/2*15 = 11*15 = 165m^2
19. Area of triangle = 1/2*bh
b = 24
h = 7
a = 24*7/2 = 168/2 = 84
Hope u understood
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Thank You
Answer:
C AND D Y=X-3 IS CONNECTING WITH C AND D AND Y=-2X+1 IS CONNECTING WITH A AND C
Step-by-step explanation:
If it takes one person 4 hours to paint a room and another person 12 hours to
paint the same room, working together they could paint the room even quicker, it
turns out they would paint the room in 3 hours together. This can be reasoned by
the following logic, if the first person paints the room in 4 hours, she paints 14 of
the room each hour. If the second person takes 12 hours to paint the room, he
paints 1 of the room each hour. So together, each hour they paint 1 + 1 of the 12 4 12
room. Using a common denominator of 12 gives: 3 + 1 = 4 = 1. This means 12 12 12 3
each hour, working together they complete 13 of the room. If 13 is completed each hour, it follows that it will take 3 hours to complete the entire room.
This pattern is used to solve teamwork problems. If the first person does a job in A, a second person does a job in B, and together they can do a job in T (total). We can use the team work equation.
Teamwork Equation: A1 + B1 = T1
Often these problems will involve fractions. Rather than thinking of the first frac-
tion as A1 , it may be better to think of it as the reciprocal of A’s time.
World View Note: When the Egyptians, who were the first to work with frac- tions, wrote fractions, they were all unit fractions (numerator of one). They only used these type of fractions for about 2000 years! Some believe that this cumber- some style of using fractions was used for so long out of tradition, others believe the Egyptians had a way of thinking about and working with fractions that has been completely lost in history.
Answer:
See explanation
Step-by-step explanation:
There are three possible cases:
1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:
