Answer:
ANSWER:
{(2,4),( 3, 6),(4, 8)} is a function
Given a relation in x and y, we say y is a function of x if for each element x in the domain, there is exactly one value of y in the range. It is a rule of correspondence between two nonempty sets, such that, to each element of the first is called domain, there correspondents one and only one element of the second is called range.
To determine whether it is function or not by using the vertical line test. If the graph passed to Vertical line test it is consider as function. The graph of function defines y as a function of x if no vertical line intersects the graph in more than one point.
The first set of ordered pairs is a function, because no two ordered pairs have the same first coordinates with different second coordinates for example ( -1, 2), ( 1, 0), (2, 1) . The second example is not a function, because it contains the ordered pairs (1,2) and (1,4). the first set is repeated . These have the same first coordinate and different second coordinates.
The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain. The range is the resulting y-values we get after substituting all the possible x-values.
You would need 6 packages for 27 students because 27 isn't divisible by 5 without a remainder and all students need pencils. So, you would need to bu another package of pencils.
Answer:
it's 8.8 had to do the exact problem on khan acedemy
Step-by-step explanation:
answer is 8.8 breaths
Answer:
x = 11, y = 17
Step-by-step explanation:
Note that
9x - 4 = 8x + 7 ( vertical angles )
Subtract 8x from both sides
x - 4 = 7 ( add 4 to both sides )
x = 11
and
7y - 34 = 5y ( vertical angles )
Subtract 5y from both sides )
2y - 34 = 0 ( add 34 to both sides )
2y = 34 ( divide both sides by 2 )
y = 17
Answer:
![\boxed{\sf \ \ \ x=\dfrac{3}{4} \ \ \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5C%20%5C%20%5C%20x%3D%5Cdfrac%7B3%7D%7B4%7D%20%5C%20%5C%20%5C%20%7D)
Step-by-step explanation:
hello,
f(x)=x-1
![g(x)=2x^2+3](https://tex.z-dn.net/?f=g%28x%29%3D2x%5E2%2B3)
so
![fog(x)=f(g(x))=f(2x^2+3)=2x^2+3-1=2x^2+2 \ and \\gof(x)=g(f(x))=g(x-1)=2(x-1)^2+3=2x^2-4x+2+3=2x^2-4x+5 \ \ So\\\fog(x)=gof(x) 2x^2+2=2x^2-4x+5\\4x=5-2=3\\x=\dfrac{3}{4}](https://tex.z-dn.net/?f=fog%28x%29%3Df%28g%28x%29%29%3Df%282x%5E2%2B3%29%3D2x%5E2%2B3-1%3D2x%5E2%2B2%20%5C%20and%20%5C%5Cgof%28x%29%3Dg%28f%28x%29%29%3Dg%28x-1%29%3D2%28x-1%29%5E2%2B3%3D2x%5E2-4x%2B2%2B3%3D2x%5E2-4x%2B5%20%5C%20%5C%20So%5C%5C%5Cfog%28x%29%3Dgof%28x%29%20%3C%3D%3E2x%5E2%2B2%3D2x%5E2-4x%2B5%5C%5C%3C%3D%3E4x%3D5-2%3D3%5C%5C%3C%3D%3Ex%3D%5Cdfrac%7B3%7D%7B4%7D)
hope this helps