By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
<h3>How to solve a system of equations</h3>
In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:
x - y = 5 (1)
x² · y = 5 · x + 6 (2)
By (1):
y = x + 5
By substituting on (2):
x² · (x + 5) = 5 · x + 6
x³ + 5 · x² - 5 · x - 6 = 0
(x + 5.693) · (x - 1.430) · (x + 0.737) = 0
There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737
And the y-values are found by evaluating on (1):
y = x + 5
x₁ ≈ 5.693
y₁ ≈ 10.693
x₂ ≈ 1.430
y₂ ≈ 6.430
x₃ ≈ - 0.737
y₃ ≈ 4.263
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
To learn more on nonlinear equations: brainly.com/question/20242917
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Answer:
A) Both estimates are slightly larger, so it is reasonable.
Step-by-step explanation:
Since 1/2 = 5/10
And 1/5 = 8/40
<u>Both estimates are larger</u>
Answer: b. 30%
Step-by-step explanation:
- A measure of relative variability is known as coefficient of variation. It is the ratio of the standard deviation to the mean.
i.e. 
Given: mean = 
Variance = 
Now, 
in percent , 
Hence, correct option is b. 30%.
Answer:
Quinn can expect to pick blue 40 times
Step-by-step explanation:
the probability of picking blue is stated as 2/10 which can be reduced to 1/5
multiply the number of times they pick a marble ( shown as 200) by the probability of picking a blue one ( 1/5)
200 x 1/5 = 200 / 5 = 40
Quinn can expect to pick blue 40 times
Answer: A) 150
You put all the numbers in numerical order, than you get the middle number of both halves which will be 300 and 450, so you find the difference of that which is 150
