Answer: 3.8 in decimal form.
Step-by-step explanation:
19/5=3.8
Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
(-2)(-5)(-7)
(10)(-7)
-70
The product is -70
Answer:
114°
Step-by-step explanation:
The exterior angle is the sum of the remote interior angles.
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<h3>setup</h3>
(11x +15)° = 60° +6x°
<h3>solution</h3>
5x = 45 . . . . . . . . . divide by °, subtract 15+6x
x = 9 . . . . . . . . . . divide by 5
The measure of exterior angle KMN is ...
m∠KMN = (11(9) +15)° = 114°
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<em>Additional comment</em>
Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...
60° +6x° +M = 180°
(11x +15)° +M = 180°
Equating these expressions for 180° and subtracting M gives the relation we used above:
(11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°
(11x +15)° = 60° +6x° . . . . . . . . . . . subtract M
This is also described by "supplements to the same angle are equal."
Answer:
The tank will empty in 4 hours.
Step-by-step explanation:
Since a barrel contains 56 liters of kerosene, and it has two taps, one tap that draws 500 ml every 6 minutes and after first 5 liters are drawn from the barrel, the second tap also starts, and it draws 1 liter in every 5 minutes, to determine how many hours will be taken in all to empty the tank, the following calculation must be performed:
0.5 x X = 5
X = 5 / 0.5
X = 10
10 x 6 = 60
1 hour = 51 liters
1 hour 30 minutes = 51 - (1 x 6) - (0.5 x 5) = 42.5
2 hours = 42.5 - (1 x 6) - (0.5 x 5) = 34
2 hours 30 minutes = 34 - (1 x 6) - (0.5 x 5) = 25.5
3 hours = 25.5 - (1 x 6) - (0.5 x 5) = 17
3 hours 30 minutes = 17 - (1 x 6) - (0.5 x 5) = 8.5
4 hours = 8.5 - (1 x 6) - (0.5 x 5) = 0
Therefore, the tank will empty in 4 hours.
