Hi there
The formula is
A=p e^rt
A future value?
P present value 475
R interest rate 0.023
T time 4 years
A=475×e^(0.023×4)
A=520.77
Hope it helps
Start with the vertex form of the equation of a quadratic. Fill in the numbers you know and solve for the one you don't know.
y = a(x -h)² +k . . . . . . . . for some stretch factor "a" and vertex (h, k)
1. Vertex = (h, k) = (0, 0). Stretch factor can be found from the given point (x, y).
8 = a(-2 -0)² +0
8 = 4a . . . . . . . . simplify
2 = a . . . . . . . . . divide by the coefficient of "a"
Your equation is y = 2x².
Note the above method for solving these problems. It repeats.
2. As above, substitute what's given and solve for what's not.
3 = a(1 -2)² +0
3 = a
Your equation is y = 3(x -2)²
3. Repeat
-4 = a(-5 +3)² +0
-4 = 4a
-1 = a
Your equation is y = -(x +3)²
4. Are you seeing the pattern yet?
0 = a(-1 -0)² +1
0 = a +1
-1 = a
Your equation is y = -x² +1
5 & 6. You know that if you want a zero (x-intercept) to be located at x=a, then a factor of the quadratic will be (x -a). Multiply the factors together to get your quadratic function.
5. y = (x -0)*(x -2) = x² -2x
6. y = (x +5)*(x -5) = x² -25 . . . . . . . . . . you should recognize this "special form", the factoring of the difference of squares
<span>Starting with 500 and creating a pattern that subtracts 4 from each number would give us an expression of x = n - 4 where x is the next number in progression and n is the current number. Using this expression we get the following sequence out to 5 numbers. 500, (500-4)=496, (496-4)=492, (492-4)=488, (488-4)=484. The final sequence is 500, 496, 492, 488, 484.</span>
The amount of 120000 should be deposit in X account in the bank as it is giving more amount of compound interest.
As given in the question we have two accounts that is X and Y.
In X account the rate of interest is 8% per annum semi annually compound interest which means 16% per annum for year.
In Y accounts the rate of interest is 12% per annum compound interest for year.
hence, if we deposit the Rs. 120000 in bank with account X then
120000×16%= 19200 [ first year interest]
139200×16%=22272[second-year interest]
the total amount of compound interest = Rs 41472.
now if we deposit in Y account then
120000×12%=14400
134400×12%=16128
the total amount of compound interest =Rs 30528
now we can see that we are getting more interest amounts in X account compared to Y.
hence, depositing the Rs.120000 in account X will be beneficial.
To know more about the compound interest click here: brainly.com/question/14295570
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