Nine and fifteen thousandth

Have Retirement Benefits

charle [14.2K]

Answer:

(a) The probability of the intersection of events "man" and "yes" is 0.55.

(b) The probability of the intersection of events "no" and "man" is 0.10.

(c) The probability of the union of events "woman" or "no" is 0.45.

Step-by-step explanation:

The information provided is:

Yes No Total

Men 275 50 325

Women 150 25 175

Total 425 75 500

(a)

Compute the probability that a randomly selected employee is a man and a has retirement benefits as follows:

$P(M\cap Y)=\frac{n(M\cap Y)}{N}=\frac{275}{500}=0.55$

Thus, the probability of the intersection of events "man" and "yes" is 0.55.

(b)

Compute the probability that a randomly selected employee does not have retirement benefits and is a man as follows:

$P(N\cap M)=\frac{n(N\cap M)}{N}=\frac{50}{500}=0.10$

Thus, the probability of the intersection of events "no" and "man" is 0.10.

(c)

Compute the probability that a randomly selected employee is a woman or has no retirement benefits as follows:

$P(W\cup N)=P(W)+P(N)-P(W\cap N)=\frac{175}{500}+\frac{75}{500}-\frac{25}{500}=0.45$

Thus, the probability of the union of events "woman" or "no" is 0.45.

5 0

3 years ago

What is the solution to the equation t + 14 = 24? 38 10 14 24

olchik [2.2K]

Answer:

10

Step-by-step explanation:

24-14=10

Do these equations backwards to find the answer you are looking for.

4 0

3 years ago

Give the domain and range of the relation.

Fofino [41]

I’am doing this rn it’s soooo hardddd!! Let me see if I know this one

6 0

3 years ago

Read 2 more answers

A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether th

ki77a [65]

Answer:

(a) A matched pair design is used to perform the test.

(b) Each sample is of size 30.

(c) The null hypothesis is rejected.

(d) The effect size of the test is medium.

Step-by-step explanation:

A statistical experiment is performed to determine whether the amount of time (in minutes) that parent-child pairs spend on social networking sites to test show any generational differences.

Given:

MD = -42 minutes

t₍₂₉₎ = 4.021

p < 0.05

d = 0.49

The hypothesis is:

H₀: There is no difference between the means, i.e. μ₁ = μ₂.

Hₐ: There is a significant difference between the means, i.e. μ₁ ≠ μ₂.

(a)

A matched pair design is used to perform the test.

In a matched pair design the participant of the two groups are related in some way. For example, the same sample is tested before and after applying the treatment.

In this case the matched are pairs are of children and their parents. And the treatment is the amount of time spent on social networking sites.

(b)

The degrees of freedom of a matched pair design is:

df = n - 1

29 = n - 1

n = 29 + 1

n = 30

Thus, each sample is of size 30.

(c)

The p-value of the test statistic is < 0.05.

If the p-value is less than the significance level α (say, 0.05) then the null hypothesis is rejected and vise-versa.

Since p < 0.05 the null hypothesis is rejected concluding that there is a significant difference between the amount of time spent on social networking sites by parents and children.

(d)

The estimated value of Cohen's d is, d = 0.49.

A Cohen's d value between the range 0.50 to 0.80 is considered as medium.

Thus, the effect size of the test is medium.

3 0

3 years ago

Do you convert 100 inches per minute to feet per minute

spin [16.1K]

Your answer would be 8.3333333 feet per minute

4 0

3 years ago

Read 2 more answers