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Mashutka [201]
3 years ago
8

What is the surface area in square feet of a rectangular prism with dimensions of 2 feet by 3 feet by 4 feet as shown in the net

?
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer: 52 square feet

Step-by-step explanation:

The surface area of a rectangular prism is given by :-

S.A.=2(lw+wh+hl), where l is length , w is width and h is height of then prism.

Given: Dimensions of the rectangular prism :   l\times w\times h= 2 feet by 3 feet by 4 feet

Then , the surface area of a rectangular prism will be:-

S.A.=2(2(3)+(3)(4)+(2)(4))\\\\\Rightarrow\ S.A.=52\text{ inches}^2

Hence, the surface area  of a rectangular prism= 52 square feet

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Bill planted 647 tulip bulbs in his flower garden.He had to plant the bulbs in rows of 20.how many rows was bill able to plant?w
Angelina_Jolie [31]

Answer:

please pretty please mark brainlist

Step-by-step explanation:

number of plants = 647

number of plants in 1 rows = 20

number of rows =

647 ÷ 20 = 32 and remainder = 7 =>

647 = 32 × 20 + 7 =>

647/20 =

(32 × 20 + 7) / 20 =

32 + 7/20 =

32 7/20

5 0
3 years ago
Find the solutions of the quadratic equation 3x^2 + 9x + 17 = 0
kirill115 [55]

Answer:

x=  

6

9−  

285

​  

 

​  

=  

2

3

​  

−  

6

1

​  

 

285

​  

=−1.314

x=  

6

9+  

285

​  

 

​  

=  

2

3

​  

+  

6

1

​  

 

285

​  

=4.314

Step-by-step explanation:

8 0
3 years ago
Check all solutions to the equation. If there are no solutions, check "None."x2=0A. 1B. -1C.0D. 10E. 4E None
Juli2301 [7.4K]

The given equation is,

\begin{gathered} x^2=0 \\ x=0 \end{gathered}

Thus, option (C) is the correct solution.

8 0
1 year ago
Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
L_y=2xyz^2+\lambda=0
L_z=2xy^2z+\lambda=0
L_\lambda=x+y+z-5=0

\lambda=-y^2z^2=-2xyz^2=-2xy^2z

-y^2z^2=-2xyz^2\implies y=2x (if y,z\neq0)

-y^2z^2=-2xy^2z\implies z=2x (if y,z\neq0)

-2xyz^2=-2xy^2z\implies z=y (if x,y,z\neq0)

In the first octant, we assume x,y,z>0, so we can ignore the caveats above. Now,

x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of f(1,2,2)=16.

We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
4 0
3 years ago
Can someone please help me ?
IRINA_888 [86]
Sure, What's up! What kinda help do you need. Give me subjects grade level.
8 0
3 years ago
Read 2 more answers
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