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solmaris [256]
3 years ago
7

Find the value of x in this figure?

Mathematics
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

Option A.

Step-by-step explanation:

We know that radius of a circle is perpendicular to its tangent at the point of tangency.

\angle OQP=90^{\circ}

According to the angle sum property, the sum of interior angles of a triangle is 180 degrees.

Using angle sum property we get

x^{\circ}+90^{\circ}+43^{\circ}=180^{\circ}

x^{\circ}+133^{\circ}=180^{\circ}

x^{\circ}=180^{\circ}-133^{\circ}

x^{\circ}=47^{\circ}

x=47

The value of x is 47.

Hence, the correct option is A.

Vitek1552 [10]3 years ago
3 0
Assuming PQ is tangent to the circle, ∠OQP = 90°

 90 + 43  + x = 180° (Sum of all angles in a triangle is 180)

x = 180 - 90 - 43 = 47°

Answer: x = 47°
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Two ships leave the same port at the same time. Two hours later ship A has traveled 12 miles and ship B has traveled 8 miles.
sashaice [31]

Answer:

the angle between their paths is <em>100.8°</em>

Step-by-step explanation:

From the given information, you can construct a triangle, just like the one in the figure.

We will use the <em>Cosine Rule</em> which is:

c² = b² + a² - 2 b c cos(θ)

where

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Therefore,

2 b c cos(θ) = b² + a² - c²

cos(θ) = (b² + a² - c²) / 2 b c

θ = cos⁻¹( (b² + a² - c²) / (2 b c) )

θ = cos⁻¹( (8² + 12² - 16²) / 2(8)(16) )

<em>θ = 100.8°</em>

<em></em>

Therefore, the angle between their paths is <em>100.8°</em>

4 0
3 years ago
5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you
zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

5^{2x-1}+5^{x+1}=250

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5^{2x}5^{-1}+5^{x}5^{1}=250

Operating:

\displaystyle \frac{5^{2x}}{5}+5^{x}5=250

Multiplying by 5:

5^{2x}+25\cdot5^x=1250

Rearranging:

5^{2x}+25\cdot5^x-1250=0

Recall that:

5^{2x}=(5^{x})^2

(5^{x})^2+25\cdot5^x-1250=0

Calling

y=5^{x}:

y^2+25y-1250=0

Factoring:

(y-25)(y+50)=0

There are two possible solutions:

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y cannot be negative, thus:

5^{x}=25=5^2

The solution is:

x = 2

8 0
3 years ago
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1: 5 2: 9 or 10

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AysviL [449]
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kykrilka [37]

Answer:

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