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Hitman42 [59]
3 years ago
14

Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,

0) and (2, 0) no solutions Mark this and return
Mathematics
2 answers:
olganol [36]3 years ago
6 0

ANSWER

No solution

EXPLANATION

The first equation is

y =  {x}^{2}  - 2x

and the second equation is

y =  - 2x  - 1

We equate the two equations to obtain;

{x}^{2}  - 2x =  - 2x - 1

This implies that

{x}^{2}  =  - 2x + 2x - 1

{x}^{2}  =  - 1

There is no real number whose square is -1.

Therefore, the equation has no solution.

egoroff_w [7]3 years ago
4 0

Answer: no solution

Step-by-step explanation: no cap

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46 is the sum of 9 and Hector's savings. Use the variable h to represent Hector's savings
AURORKA [14]
H+9=46
it would be a decimal
7 0
3 years ago
Show calculations for each of the ratio table
Sladkaya [172]

Answer:

From left to right:

3, 30, 20

Step-by-step explanation:

Start by determining the ratio of yellow to red paint. Use the column where both amounts are given:

yellow to red = 2 to 6 = 1 to 3

2 to 6 the same as 1 to 3 when reduced, by dividing both sides by 2.

This means yellow paint is a third of red paint. Backwards, red paint is three times yellow paint.

To go from yellow to red, do yellow X 3.

To go from red to yellow, do red ÷ 3.

Column 1:

1 X 3 = 3

Column 3:

10 X 3 = 30

Column 4:

60 ÷ 3 = 20

The ratios are:

1 to 3

2 to 6

10 to 30

20 to 60

4 0
4 years ago
The original cost of a lamp is $18.95 . The lamp is on sale for 75% off . How much will you pay ?
gregori [183]
18.95x0.75=14.2125

18.95-14.2125=4.73

You will pay $4.73
7 0
3 years ago
Read 2 more answers
Which costs more per gallon? 5 gallons for $12.50 or 11 gallons for $26.40
Effectus [21]

Answer: 5

Step-by-step explanation:

If;

5 gallons = $12.50 / 5 = $2.50/gallon

11 gallons = $26.40 / 11 = $2.40/gallon

In conclusion, 5 gallons cost more per gallon than 11.

6 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
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