Question

Solve these equations: 1. 2(n+1)+1=(n-5)+(n-2) 2. 3(n-1)-2=4(n-4)-(n-1)

Answer 1

Hope this helps. Good luck

Answer 2

Hey there!!

First equation :

Given equation :

... 2 ( n + 1 ) + 1 = ( n - 5 ) + ( n - 2 )

Excluding the parenthesis and using the distributive property :

... 2n + 2 + 1 = n - 5 + n - 2

Combining all the like terms on each side :

... 2n + 3 = 2n - 7

Subtracting 2n and subtracting 3 on both sides :

... 0 = -10

Hence, the first equation has "zero" values.

Second equation :

Given equation :

... 3 ( n - 1 ) - 2 = 4 ( n - 4 ) - ( n - 1 )

Using the distributive property :

... 3n - 3 - 2 = 4n - 16 - n + 1

Combining all the like terms :

... 3n - 5 = 3n - 15

Adding 5 and subtracting 3n on both sides :

... 0 = -10

Hence, the second equation has "zero" values.

Hope my answer helps!!